Answer:
I THINK ITWORKS
TRY IT
solve for the values of A and B and C and D with full workings and solution (this problem is from my 5th grade math book, just for fun)
3y 2 z(2y 2 z + 4yz - y + z)
Answer: 48(y*z)^2 - 6z*y^2 - 6y*z^2
Step-by-step explanation: We want to find the product:
3y*2z*(2y*2z + 4yz - y - z)
First, distribute the product:
3y*2z*2y*2z + 3y*2z*4yz -*3y*2z*y - 3y*2z*z
now, let's simplify the equation:
(3*2*2*2)(y*z)^2 + (3*2*4)(y*z)^2 - (3*2)z*y^2 - (3*2)y*z^2
24(y*z)^2 + 24(y*z)^2 - 6z*y^2 - 6y*z^2
48(y*z)^2 - 6z*y^2 - 6y*z^2
If the equation you want to distribute is:
(3y^2z)*(2y^2z + 4yz - y - z)
the distribution is:
(3y^2z)´*(2y^2z) + (3y^2z)*4yz -(3y^2z)*y - (3y^2z)*z
6y^4z + 12y^(2z + 1)*z - 3y^(3z + 1) - (3y^2z)*z
x = 3^√10 + 12
Is the right answer 100%