The combined land area of the countries A and B is 157,973 square kilometers. Country A is larger by 773 square kilometers. Determine the land area of each country.

Answers

Answer 1

Answer: The combined land areas of country A & B are 157,973 sq km. COuntry A is larger by 773 sq kn. The land area of Country A is 79,373, the land area of Country B is 78,600.

Answer 2

Answer: A + B = 157,973
A = B + 773

now its just a matter of subbing
(B + 773) + B = 157,973
2B + 773 = 157,973
2B = 157,973 - 773
2B = 157,200
B = 157,200/2
B = 78,600 <=== land area for country B

A = B + 773
A = 78,600 + 773
A = 79,373 <== land area for country A

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Divide (15x^2+x-8)/(3x-1)

Answers

Simplifying -15x2 + -2x + 8 = 0
Reorder the terms: 8 + -2x + -15x2 = 0 Solving 8 + -2x + -15x2 = 0 Solving for variable 'x'.
Factor a trinomial. (2 + -3x)(4 + 5x) = 0 Subproblem 1Set the factor '(2 + -3x)' equal to zero and attempt to solve:
Simplifying 2 + -3x = 0 Solving 2 + -3x = 0
Move all terms containing x to the left, all other terms to the right. Add '-2' to each side of the equation. 2 + -2 + -3x = 0 + -2
Combine like terms: 2 + -2 = 0 0 + -3x = 0 + -2 -3x = 0 + -2
Combine like terms: 0 + -2 = -2 -3x = -2
Divide each side by '-3'. x = 0.6666666667
Simplifying x = 0.6666666667
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Set the factor '(4 + 5x)' equal to zero and attempt to solve:
Simplifying 4 + 5x = 0
Solving 4 + 5x = 0
Move all terms containing x to the left, all other terms to the right.
Add '-4' to each side of the equation. 4 + -4 + 5x = 0 + -4
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Find three ordered pairs for x=9

Answers

Three examples are (9, 1), (9, -5), and (9, 3.2).

How many roots do the following equations have? -12x^2 - 25x+5 +x^3=0

Answers

Answer:

There are 3 roots of the given equation.

Step-by-step explanation:

Given the equation

$-12x^2-25x+5+x^3=0$

we have to tell the number of roots of the given equation.

As the number of roots for an equation is equal to degree.

The degree of a polynomial is the highest power of its monomials with non-zero coefficients.

Hence, number of roots is the highest power in the equation.

Now, the equation is $-12x^2-25x+5+x^3=0$

The highest power i.e degree of equation is 3.

hence, there are 3 roots of the given equation.

$-12x^2 - 25x + 5 + x^(3) = 0$
$x^(3) - 12x^(2) - 25x + 5 = 0$
$x = \sqrt[3]{((-b^(3))/(27a^(3)) + (bc)/(6a^(2)) - (d)/(2a)) + \sqrt{((-b^(3))/(27a^(3)) + (bc)/(6a^(2)) - (d)/(2a))^(2) + ((c)/(3a) - (b^(2))/(9a^(2)))^(3)}} + \sqrt[3]{((-b^(3))/(27a^(3)) + (bc)/(6a^(2)) - (d)/(2a)) - \sqrt{((-b^(3))/(27a^(3)) + (bc)/(6a^(2)) - (d)/(2a))^(2) + ((c)/(3a) - (b^(2))/(9a^(2)))^(3)}} - (b)/(3a)$
$x = \sqrt[3]{((-(-12)^(3))/(27(1)^(3)) + ((-12)(-25))/(6(1)^(2)) - (5)/(2(1))) + \sqrt{((-(-12)^(3))/(27(1)^(3)) + ((-12)(-25))/(6(1)^(2)) - (5)/(2(1)))^(2) + ((-25)/(3(1)) - (-(-25)^(2))/(9(1)^(2)))^(3)}} + \sqrt[3]{((-(-12)^(3))/(27(1)^(3))}} + ((-12)(-25))/(6(1)^(2)) - (5)/(2(1))) - \sqrt{((-(-12)^(3))/(27(1)^(3)) + ((-12)(-25))/(6(1)^(2)) - (5)/(2(1)))^(2) + ((-25)/(3(1)) - (-(-25)^(2))/(9(1)^(2)))^(3) - (-12)/(3(1))}}$
$x = \sqrt[3]{((-(-1728))/(27(1)) + (300)/(6(1)) - (5)/(2)) + \sqrt{((-(-1728))/(27(1)^(3)) + (300)/(6(1)) - (5)/(2))^(2) + ((-25)/(3(1)) - (144)/(9(1)))^(3)}}} + \sqrt[3]{((-(-1728))/(27(1)) + (300)/(6(1)) - (5)/(2)) - \sqrt{((-(-1728))/(27(1)^(3)) + (300)/(6(1)) - (5)/(2))^(2) + ((-25)/(3(1)) - (144)/(9(1)))^(3)}}} - (-12)/(3)$
$x = \sqrt[3]{((1728)/(27) + (300)/(6) - 2(1)/(2)) + \sqrt{((1728)/(27) + (300)/(6) - 2(1)/(2))^(2) + ((-25)/(3) - (144)/(9))^(3)}} + \sqrt[3]{((1728)/(27) + (300)/(6) - 2(1)/(2)) - \sqrt{((1728)/(27) + (300)/(6) - 2(1)/(2))^(2) + ((-25)/(3) - (144)/(9))^(3)}} - 4$
$x = \sqrt[3]{(64 + 50 - 2(1)/(2)) + \sqrt{(64 + 50 - 2(1)/(2))^(2) + (-8(1)/(3) - 16)^(3)}} + sqrt[3]{(64 + 50 - 2(1)/(2)) - \sqrt{(64 + 50 - 2(1)/(2))^(2) + (-8(1)/(3) - 16)^(3)}} - 4$
$x = \sqrt[3]{(114 - 2(1)/(2)) + \sqrt{(114 - 2(1)/(2))^(2) + (-24(1)/(3))^(3)}} + \sqrt[3]{(114 - 2(1)/(2)) - \sqrt{(114 - 2(1)/(2))^(2) + (-24(1)/(3))^(3)}} - 4$
$x = \sqrt[3]{(112(1)/(2)) + \sqrt{(112(1)/(2))^(2) - (24(1)/(3))^(3)}} - \sqrt[3]{(112(1)/(2)) + \sqrt{(112(1)/(2))^(2) - (24(1)/(3))^(3)}} - 4$
$x = \sqrt[3]{112(1)/(2) + √(12656.25 - 14408.037)} + \sqrt[3]{112(1)/(2) + √(12656.25 - 14408.037)} - 4$
$x = \sqrt[3]{112(1)/(2) + √(-1751.787)} + \sqrt[3]{112(1)/(2) - √(-1751.787)} - 4$
$x = \sqrt[3]{112(1)/(2) + 41.855i} + \sqrt[3]{112(1)/(2) - 41.855i} - 4$
$x = -4 + \sqrt[3]{112(1)/(2) + 41.855i} + \sqrt[3]{112(1)/(2) - 41.855i}$

Write the equation of the line whose slope is m=−9 and y-intercept is (0,5) in Slope Intercept Form. Show all work below.

Answers

Y=mx+b is slope intercept form...
m=slope
b=y-intercept
Answer- y=-9+5

Answer:

y = -9x +5

Step-by-step explanation:

y = mx+b

x = what you multiply the slope by

b (y-int) = the y-intercept

y = y

what is the common ratio for the geometric sequence below, written as a faction? 768,480,300,187.5,...

Answers

To determine the common ratio of the geometric sequence, divide the second term with the first term. 480 divided by 768 equals 5/8. Further, the ratio of the third and second terms may be used to check the consistency of the common ratio. The ratio is also 5/8. Thus, the common ratio is 5/8.

Write the word sentence as an inequality.

A number a is more than 6.

Answers

a>6 i hope this helps

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