Answer:
11.70469991
Step-by-step explanation:
B. making a note of each expense so that she does not repeat purchases
C. preparing a report for her bank on how she spends money
D. preparing a budget to review her expenses
Answer:
D is the right answer.
Step-by-step explanation:
Given that Sarah used to maintain a log of each time she spends or receives money.
Logs are maintained normally for money receipt and payment for the following reasons.
i) To know accurate the cash balance in hand at any time
ii) To estimate the purchases still due
iii) to plan for utilizing the available money for effective uses,
iv) to prepare a budget to review her expenses
Out of the four options the last option seems to be more appropriate for this.
The equation for the aircraft's flight is a quadratic equation representing the height of the aircraft at any given time. By rearranging the equation to isolate time and applying the quadratic formula, we can find the time at which the aircraft reaches its maximum height, which in this case is 3.79 minutes.
The flight of an aircraft from Toronto to Montreal is modeled by the equation h = -2.5t2 + 200t where t represents time in minutes and h represents height in meters. This is fundamentally a quadratic equation which is utilized in physics to characterize motion under constant acceleration. In this case, it models the height of the aircraft at any given time.
To find the time at which the airplane's maximum height is achieved, we must solve the equation for t. By rearranging the equation, we can isolate t, yielding a quadratic equation as follows: 0 m = 0 m + (10.0 m/s) t + (2.00 m/s2) t2. This simplifies to 200 = 10t + t2.
Applying the quadratic formula, we find two solutions for t, 3.79 s and 0.54 s. The time it takes the aircraft to reach its maximum height would be the longer solution, which is 3.79 minutes in this case.
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The question provides a quadratic equation to model the flight of an aircraft. This equation can be used to calculate the height of the aircraft at a specific time or to determine when the aircraft reaches its maximum height.
The question is asking about the trajectory of an aircraft as modelled by a quadratic equation, and specifically, how time influences height. The equation given is h = -2.5t²+200t. Quadratic equations are frequently used to describe the motion of objects when the acceleration is constant. This equation tells us that the height of the aircraft is dependent on the time squared and the time.
To solve for a specific time (t), we can plug the desired time into the equation to find the height of the aircraft at that time. For instance, if we want to find out the height of the aircraft 10 minutes into the flight, we would substitute t=10 into the equation, giving us h=-2.5 × (10)²+200 × (10). Simplifying this equation would provide the height of the aircraft 10 minutes into the flight.
Additionally, this equation could also be used to find the maximum height of the aircraft. The maximum height is reached when the derivative of the equation equals zero. Taking the derivative of h = -2.5t²+200t and setting it equal to zero will provide the time when the maximum height is reached.
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Rotating 90° clockwise from quadrant 2 means you are reflecting over the y-axis into quadrant 1. What do quadrant 1 coordinates look like? both x and y are positive and are reversed.
(-x, y) → (y, x)
A: (-8, 1) → (1, 8)
B: (-6, 4) → (4, 6)
C: (-2, 1) → (1, 2)
A. (-8, 1) → (1, 8)
C. (-2, 1) → (1, 2)
im so sorry but i dont know what b. is hope this helps tho :)