Answer:
Inorganic impurities present in the bulk of a liquid such as KCl tend to increase the surface tension of water.
Explanation:
As potassium chloride (KCl) dissolves in water, the ions are hydrated. ... When ionic compounds dissolve in water, the ions in the solid separate and disperse uniformly throughout the solution because water molecules surround and solvate the ions, reducing the strong electrostatic forces between them.
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(ii) 2-bromo-2-methylpentane.
Answer:
The mechanisms for the elimination reactions between NaOH in ethanol and the halogenoalkanes are demonstrated in the figure attached.
Explanation:
(i) 1-bromobutane will suffer elimination to for an alkene. The mechanism will be E2, which means that the attack and the elimination will occur simultaneously. This is the preferred mechanism because the bromine is in a primary carbon.
(ii) 2-bromo-2-methylpentane will suffer elimination to for an alkene. The mechanism will be E1, which means that the attack and the elimination will occur in two different steps. The bromine will be eliminated in the first step with the formation of a carbocation and in a second step the double bond will be formed after the anionic attack. This is the preferred mechanism because the bromine is in a terciary carbon which is able to stabilize the carbocation formed.
Answer:
Addition of some Na₂SO₄ (aq).
Explanation:
2NaHCO₃ (s) + H₂SO₄ (aq) ⇄ Na₂SO₄ (aq) + 2H₂O (l) + 2CO₂ (g)
According to the Le Chatelier's principle, the addition of Na₂SO₄ to the reaction would lead to shift to the direction of the reaction that consumes Na₂SO₄, in order to reestablish equilibrium. Since the reaction that consumes Na₂SO₄ is the reaction that produces H₂SO₄, the concentration of H₂SO₄ would increase.
Asnwer : Empirical formula of a compound is :
Given information : C = 64.3 % , H = 7.2 % , O = 28.5 %
Step 1 : Convert the given percentage (%) to grams.
Explanation : Let the total mass of the compound be 100 grams.
Mass of C = 64.3 g
Mass of H = 7.2 g
Mass of O = 28.5 g
Step 2 : Convert the grams of each compound to moles.
Molar mass of C = 12.0g/mol
Molar mass of H = 1.0 g/mol
Molar mass of O = 16.0g/mol
Moles of C = 5.36 mol
Moles of H = 7.2 mol
Moles of O = 1.78 mol
Step 3 : Find the mole ratio of C , H and O
Mole ratio is calculated by dividing the mole values by the smallest value.
Mole of C = 5.36 mol , Mole of H = 7.2 mol , Mol of O = 1.78 mol
Out of the three mole values , mole value of O that is 1.78 mol is less , so we divide all the mole values by 1.78 mol.
C : H : O = 3 : 4 : 1
So empirical formula of the compound is or
B)Leave the gas stop open for a few minutes before lighting to clear the line.
C)Clear the burner area of flammable materials such as solvents and papers.
D)Check that the gas regulator and air inlet on the burner can be adjusted.
The Bunsen burner is a heating apparatus used to heat samples in the laboratory. The correct answer is option B: )Leave the gas stop open for a few minutes before lighting to clear the line.
A Bunsen burner is commonly used as a heating apparatus. It contains a gas that can be controlled using a gas regulator.
It is necessary to do the following before lighting the Bunsen burner;
So, it is not necessary to Leave the gas stop open for a few minutes before lighting to clear the line before lighting a Bunsen burner.
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Answer:
the answer is opetuon B
oxygen (0)
fluorine (F)
argon (Ar)
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Argon (Ar) has a complete valence electron shell.
The element that has a complete valence electron shell is argon (Ar).