Answer:
A and C are the answer
Step-by-step explanation:
hope it helps bye!!
Answer:
Step-by-step explanation:
2 3/4 ÷ 4 1/8
23/4×8/41
23×8/4×41
46/41
=1.122
So the answer is 1.122
The solution after divide 2 3/4 by 4 1/8 in fraction form is,
⇒ 2/3
We have to given that,
To divide 2 3/4 by 4 1/8.
Simplify it as,
2 3/4 ÷ 4 1/8
11/4 ÷ 33/8
11/4 x 8/33
(11 x 8) / (4x33)
2/3
Therefore, The solution after divide 2 3/4 by 4 1/8 in fraction form is,
⇒ 2/3
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It can be written as 5 x 10^ -11 or 0.5 x 10^ -10
Hope it helps.
Answer: 1 out of 4
Step-by-step explanation:
If you divided the total amount of balloons that were sold by the amount of white balloons, it would be 4. The 1 comes from 1 in 4 being the probability of them being white. You can check this by multiplying the 1 and 4 by 6 and it would be 6 out of 24, which shows our answer is correct.
Answer:4/15 i'm doing it and that was the answer
Step-by-step explanation:
Answer:
a) probability that neither is Tay-Sachs carrier is 0.9298
b) the probability that both are carriers is 0.001276
Step-by-step explanation:
Given that;
1 in 28 people of Ashkenazi jewish descent are Tay-Sachs carrier.
so P(Carrier) = 1/28 =
also P( Not a carrier) = 1 - 1/28 = 0.9643
Now After Sampling 1 man and 1 woman from the population;
a)
the probability neither is Tay-Sachs carrier
P( Neither is a Carrier) = 27/28 × 27/28 = 0.9298
Therefore probability that neither is Tay-Sachs carrier is 0.9298
b)
the probability both are carriers
P( Both are Carriers) = 1/28 × 1/28 = 0.001276
Therefore the probability that both are carriers is 0.001276
The probability of both a man and a woman of Ashkenazi Jewish descent not being Tay-Sachs carriers is calculated as (27/28) * (27/28). The probability of both being carriers is (1/28) * (1/28).
The probability of an event occurring is calculated as the number of favorable outcomes divided by the total number of outcomes. In this case, the problem is related to genotypes and their associated probabilities, aligning with the concept of probability in mathematics.
The probability of a person of Ashkenazi Jewish descent not being a Tay-Sachs carrier is 27/28 because 1 out of 28 are carriers, and thus 27 out of 28 are not. For two independent events, the probability of both occurring is obtained by multiplying their individual probabilities. Therefore, the probability of both the man and the woman not being carriers is (27/28) * (27/28).
Similarly, the probability that both are carriers would be calculated as (1/28) * (1/28).
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Answer:
Step-by-step explanation:
There are lots of ways we can think about the typical number of cavities.
The most patients had 0cavities.
If we split the cavities evenly, each patient would have 2 or 3 cavities.
If we put our dot plot on a balance scale, it would balance when the pivot was between 2 and 3 cavities.
The scale would tip if, for example, we put the pivot at 5 cavities.
There are 8 patients with 2 cavities each. About half of the rest of the patients have fewer than 2 cavities and about half have more than 2 cavities.
Of the choices, it is reasonable to say that a patient typically had about 2 cavities.
, -Written in
The 'typical' number of cavities one patient had can be determined by finding the mode (most common number) in the data set, which should be represented in the dot plot. To do this, one would count the number of dots at each value on the dot plot. The value with the most dots would be the 'typical' number of cavities.
The question is asking for a 'typical' number of cavities one patient had out of Dr. Vance's 63 patients. In statistics, a typical, or 'common', value can be shown by calculating the mode, which is the number that appears most frequently in a data set.
Unfortunately, the dot plot is missing from the information provided. However, to find the mode (or typical value) using a dot plot, you would typically count how many dots are at each value on the plot. The value with the most dots (indicating the most patients with that number of cavities) is the mode. This would be the 'typical' number of cavities a patient of Dr. Vance had last month.
Let's create a hypothetical scenario. If your dot plot looked like this:
The mode would be 2 cavities because 24 patients had this amount, more than any other amount. Therefore, the 'typical' number of cavities one patient had would be 2.
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