Estimate a 15% tip for a $27.60 bill.

Answers

Answer 1

Answer:

Answer:

$4.2=tip value

$32.2=total value

Step-by-step explanation:

to estimate means to round to make it easier and i rounded 27.60 to 28 and 15% of 28 is 4.2, then to find the total value add the tip to the bill cost 4.2+28 to get 32.2 so its around 32.2 dollars

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Multiply. Enter your answer in scientific notation.(7 x 10^*13) (3.39 x 10^*5)=

What is 3 expressions where the solution is 4

Answers

(8x2)-12
(2^2)+9-(8+1)
17-(5x3)

What is the value of p? 13^2 = p

Answers

169 if you take 13 times 3 you get 39. And 10 times 13 is 130. Add those together and you gat 169

How do you factor 3x^2-7x-2

Answers

3x^2-7x-2

doesn't factor

You can not factor this

I hope that's help !

A 4.0-kg cart moving due east at 9.0 m/s collides with a 3.0-kg cart moving due west. The carts stick together and come to rest after the collision. What was the initial speed of the 3.0-kg cart?

Answers

Since the carts stick together and come to rest after the collision, the initial speed of the 3.0-kg cart is 12 m/s.

Given the following data:

Mass of cart 1 = 4.0 kg

Velocity of cart 1 = 9.0 m/s

Mass of cart 2 = 3.0 kg

To find the initial speed of the 3.0-kg cart, we would apply the law of conservation of momentum:

For a perfectly inelastic collision:

$M_1V_1 - M_2V_2 = V_f(M_1 + M_2)$

When the carts stick together and come to rest after the collision, the final velocity is zero (0).

$M_1V_1 - M_2V_2 = 0\n\nM_1V_1 = M_2V_2\n\nV_2 = (M_1V_1)/(M_2)$

Substituting the given parameters into the formula, we have;

$V_2 = (4(9))/(3)\n\nV_2 = (36)/(3)$

Initial speed = 12 m/s

X-y+z=-4

3x+2y-z=5

-2x+3y-z=15

How do I solve this?

Answers

$1)\ \ \ x-y+z=-4\ \ \ \Rightarrow\ \ \ z=-4-x+y\n\n2)\ \ \ 3x+2y-z=5 \n.\ \ \ \ \Rightarrow\ \ 3x+2y-(-4-x+y)=5 \n.\ \ \ \ \Rightarrow\ \ 3x+2y+4+x-y=5 \n.\ \ \ \ \Rightarrow\ \ 4x+y=1\n\n3)\ \ \ -2x+3y-z=15\n.\ \ \ \ \Rightarrow\ \ -2x+3y-(-4-x+y)=15\n.\ \ \ \ \Rightarrow\ \ -2x+3y+4+x-y=15\n.\ \ \ \ \Rightarrow\ \ -x+2y=11\n--------------------\n$

$z=-4-x+y\n.\ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ \ and\n \left \{ {{4x+y=1\ \ \ \ } \atop {-x+2y=11\ /\cdot4}} \right. \n\n\left \{ {{4x+y=1\ \ \ \ } \atop {-4x+8y=44}} \right. \n-------\ny+8y=1+44\n9y=45\ /:9\ny=5\n\n-x+2y=11\ \ \ \Rightarrow\ \ \ x=2y-11\ \ \ \Rightarrow\ \ \ x=2\cdot5-11=-1\n\nz=-4-x+y=-4-(-1)+5=-4+1+5=2\n\nAns.\ x=-1\ \ \ and\ \ \ y=5\ \ \ and\ \ \ z=2$

Solve each equation (quadratic pattern) $2^(2x) -2^(x) =12$

$3^(2x) + 3^(x+1) =4$

$4^(x) + 6$ · $2^(x) +8 = 0$

$9^(x) = 3^(x) +6$

Answers

Answer: x = 2

Step-by-step explanation:

$2^(2x)-2^x-12=0\n\n\text{Let u = }2^x\n\nu^2-u-12=0\n(u-4)(u+3)=0\n\nu-4=0\quad and\quad u+3=0\nu=4\qquad and\quad u=-3\n\n\text{Substitute u with }2^x\n2^x=4\qquad and \quad 2^x=-3\n2^x=2^2\quad and\quad \text{not possible}\n\boxed{x=2}$

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Answer: x = 0

Step-by-step explanation:

$3^(2x)+3^(x+1)-4=0\n\n3^(2x)+3^x\cdot3^1-4=0\n\n\text{Let u = }3^x\nu^2+3u-4=0\n\n(u+4)(u-1)=0\n\nu+4=0\quad and\quad u-1=0\nu=-4\qquad and\quad u=1\n\n\text{Substitute u with }3^x\n3^x=-4\qquad and\quad 3^x=1\n\text{not possible}\ and\quad 3^x=3^0\n.\qquad \qquad \qquad \qquad \boxed{x=0}$

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Answer: No Solution

Step-by-step explanation:

$4^x+6\cdot 2^x+8=0\n\n2\cdot 2^x+6\cdot 2^x+8=0\n\n\text{Let u = }2^x\n2u+6u+8=0\n8u+8=0\n8u=-8\nu=-1\n\n\text{Substitute u with }2^x\n2^x=-1\n\text{not possible}$

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Answer: No Solution

Step-by-step explanation:

$9^x=3^x-6\n\n3\cdot 3^x=1\cdot 3^x-6\n\n\text{Let u = }3^x\n\n3u=u-6\n2u=-6\nu=-3\n\n\text{Substitute u with }3^x\n3^x=-3\n\text{not possible}$

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