Answer:
d) The additional training did not significantly lower the defect rate
Step-by-step explanation:
Let proportion of defective chips be = x
Null Hypothesis [H0] : Additional training has no impact on defect rate x = 8% = 0.08
Alternate Hypothesis [H1] : Additional training has impact on defect rate x < 8% , x < 0.08
Observed x proportion (mean) : x' = 27 / 450 = 0.06
z statistic = [ x' - x ] / √ [ { x ( 1-x ) } / n ]
( 0.06 - 0.08 ) / √ [ 0.08 (0.92) / 450 ]
= -0.02 / √ 0.0001635
= -0.02 / 0.01278
z = - 1.56
Since calculated value of z, 1.56 < tabulated value of z at assumed 0.01 significance level, 2.33
Null Hypothesis is accepted, 'training didn't have defect rate reduction impact' is concluded
Simplify your answer as much as possible.
After removing the parentheses using the distributiveproperty, the expression simplifies to
We have,
To remove the parentheses using the distributiveproperty, we need to multiply each term inside the parentheses by the term outside the parentheses.
Applying the distributiveproperty to the expression we have:
Multiplying the terms:
Therefore,
After removing the parentheses using the distributiveproperty, the expression simplifies to
Learn more about expressions here:
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Answer:
i think it 29.92 but there another question like this
Step-by-step explanation:
.
Answer:
the answer is
Step-by-step explanation:
Answer:
−30+(−40)+(−70) = -140
Step-by-step explanation:
−30+(−40)+(−70) = -140
Answer:
not what im looking for
Step-by-step explanation:
Answer:
-3.9
Step-by-step explanation: