8) Which equations below would be parallel by just looking at theequations

1. y=2x + 10 and y= 3x -12
2. y= 4x -2 and y= 4x + 3
3. y=10 and y= 15x
4. not given

Answers

Answer 1
Answer:

Answer: y=4x-2 and y=4x+3


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Problem 8-19 Because of high tuition costs at state and private universities, enrollments at community colleges have increased dramatically in recent years. The following data show the enrollment (in thousands) for Jefferson Community College for the nine most recent years. Click on the datafile logo to reference the data. Year Period (t) Enrollment (1,000s) 1 1 6.5 2 2 8.1 3 3 8.4 4 4 10.2 5 5 12.5 6 6 13.3 7 7 13.7 8 8 17.2 9 9 18.1 Use simple linear regression analysis to find the parameters for the line that minimizes MSE for this time series.If required, round your answers to two decimal places.y-intercept, b0 = 4.7.17Slope, b1 = 1.46MSE = ???????? NEED THISWhat is the forecast for year 10? 19.283Round your interim computations and final answer to two decimal places.
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In a large university, 20% of the students are business majors. A random sample of 100 students is selected, and their majors are recorded. a) Compute the standard error of the proportion. b) What is the probability that the sample contains at least 12 business majors

Answers

Answer:

a. 0.04

b. 0.9772

Step-by-step explanation:

Please check attachment for complete solution and step by step explanation

Final answer:

The standard error of the proportion is 0.04. The probability of having at least 12 business students in a sample of 100 can be found by using the binomial distribution formula, though precise calculation would require the use of statistical software.

Explanation:

In a large university, 20% of students are business majors. The question is asking about the standard error and the probability of having at least 12 business students in a random sample of 100 students.

a) The standard error (SE) of the proportion is calculated as the square root of [p(1-p)/n], where 'p' is the proportion of business majors (0.2 in this case)and 'n' is the sample size (100 in this case). So, the SE = sqrt[(0.2)(0.8)/100] = sqrt[0.0016] = 0.04.

b) In order to calculate the probability that there are at least 12 business students, we would use the binomial distribution. Using the binomial distribution formula P(X >= x) = 1 - P(X < x), where 'X' is a random variable representing the number of business majors, and 'x' is 12. Since the calculation is tedious, one would use statistical software or a calculator to find this probability. Typically, the result would be greater than 0.

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Give two examples of addition of two mixed numbers with different denominators
SHOW ALL STEPS

Answers

Answer:

First Example: 3 1/2 + 4 3/4, Second Example: 6 3/8 + 7 9/15

Extra Example: 8 4/20 + 3 5/10

Step-by-step explanation:

First Example:

1/2 + 3/4

1/2 is equal to 2/4 so it is now compatible to be added to 3/4.

2/4 + 3/4

= 5/4

Now for the mixed numbers since its 3 and 4, 3 + 4 = 7.

Final answer is 7 5/4.

Second Example:

3/8 + 9/15

9/15 can be reduced to 3/5

Now the equation is 3/8 + 3/5

= 15/40 + 24/40 is an equivalent equation

15/40 + 24/40  

= 39/40

Now for the mixed numbers since its 6 and 7, 6 + 7 = 13

Final answer is 13 39/40.

I am going to include one last example just in case you need one:

Third Example:

4/20 + 5/10

We can reduce these to

1/5 + 1/2

= 2/10 + 5/10 is the equivalent equation

2/10 + 5/10

= 7/10

Now for the mixed numbers since its 8 and 3, 8 + 3 = 11.

Final answer is 11 7/10.

I Hope this helps!

Someone hurry and help plsss

Answers

Answer:

-3 is the answer for the question

2 mi. yd. I'm confused​

Answers

Answer && Step-by-step explanation:

Obtain yards by multiplying miles by 1760

== 3520 yards

Use the equation below to calculate the average speed for each problem, then complete the data table below. Problem Distance Time Speed Distance/Time 1. Ron walks 22.5 km in 5 hours, find his speed. 22.5 km 5 hours 22.5km/ 5hr= 4.5 km/hour 2. A train covers 168 km in 4 hours. Find its speed. 3. Rachel travelled 240 km in 4 hours by train and then travelled 120 km in 3 hours by car and 3 km in 1/2 hour by cycle. What is the average speed during the whole journey? 4. A car moves from A to B at a speed of 50 km/hr and comes back from B to A at a speed of 30 km/hr. Find its average speed during the journey.

Answers

1. Answer is 4.5 km / hr.

... because you divide the time but the distance so for this question you divide 22.5 by 5 and that's your answer. do the same for every question! hope this helps.

(/25) 11111111.11111111.11111111.10000000 dotted decimal subnet mask equivalent: ________________________________ number of subnets? ________________, number of hosts? ________________ (/26) 11111111.11111111.11111111.11000000 dotted decimal subnet mask equivalent: ________________________________ number of subnets? ________________, number of hosts? ________________ (/27) 11111111.11111111.11111111.11100000 dotted decimal subnet mask equivalent: ________________________________ number of subnets? ________________ number of hosts? ________________ (/28) 11111111.11111111.11111111.11110000 dotted decimal subnet mask equivalent: ________________________________ number of subnets? ________________ number of hosts? _________________ (/29) 11111111.11111111.11111111.11111000 dotted decimal subnet mask equivalent: ____

Answers

Count the number of 1 bits after the last decimal point. Call this number n.

There will be 2^n subnets and 2^(8-n) - 2 hosts per subnet. (You can mutilply the number of subnets by the number of hosts per subnet to find the total number of hosts.)

/25: 255.255.255.128, 2 subnets, 126 hosts per subnet

/26: 255.255.255.192, 4 subnets, 62 hosts per subnet

/27: 255.255.255.224, 8 subnets, 30 hosts per subnet

/28: 255.255.255.240, 16 subnets, 14 hosts per subnet

/29: 255.255.255.248, 32 subnets, 6 hosts per subnet

Final answer:

This answer explains subnet mask equivalents and calculates the number of subnets and hosts for different subnet mask values.

Explanation:

Subnet Mask Equivalents and Number of Subnets and Hosts

1. (/25) 11111111.11111111.11111111.10000000 dotted decimal subnet mask equivalent:

Subnet mask equivalent: 255.255.255.128, Number of subnets: 2, Number of hosts: 126

2. (/26) 11111111.11111111.11111111.11000000 dotted decimal subnet mask equivalent:

Subnet mask equivalent: 255.255.255.192, Number of subnets: 4, Number of hosts: 62

3. (/27) 11111111.11111111.11111111.11100000 dotted decimal subnet mask equivalent:

Subnet mask equivalent: 255.255.255.224, Number of subnets: 8, Number of hosts: 30

4. (/28) 11111111.11111111.11111111.11110000 dotted decimal subnet mask equivalent:

Subnet mask equivalent: 255.255.255.240, Number of subnets: 16, Number of hosts: 14

5. (/29) 11111111.11111111.11111111.11111000 dotted decimal subnet mask equivalent:

Subnet mask equivalent: 255.255.255.248

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