The area of the diagonal section of a cube is equal to 36Ì2. Determine the edge and the diagonal of the cube.? please help me thank you :)

Answers

Answer 1
Answer: The answer is the edge of the cube is 6 and the diagonal of the cube is 6√3
 
The diagonal section of a cube is a rectangle with sides a and x, where a is the edge of the cube, and x is a diagonal of a side of the cube. Therefore, the area of a diagonal section (A) is:
A = a * x
Now, a = ? and x = ?, but we know that the side of the cube is square and its diagonal is x = a√2.

So, we have:
A =  36√2
a = ?
x = a√2

Let's substitute all parameters in the formula for the area:
A = a * x
36√2 = a * a√2

Divide both sides by √2:
36 = a * a
36 = a²
⇒ a =√36 = 6

The diagonal of the cube can be calculated by using the formula: d = a√3
Since a = 6, then:d = 6√3

Therefore, the edge of the cube is 6 and the diagonal of the cube is 6√3.

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Answers

1.  2r-5
2.  -21r-50
3.  4r-50
4.  14r+50
5.  19r-50

If a plane departed at 12:30 A.M. and arrived at 8:15 A.M., what was the length of time for the flight?

Answers

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What is the solution to the system of equations? Use the substitution method.y=3x-4
9x-3y=14

A. There is no solution
B. (12, 14)
C. (14, 12)
D. There an infinite number of solutions.

Answers

{ y = 3 x - 4
  9x -3y = 14

Subsititute y = 3x-4 :

[ 9 x - 3 ( 3 x-14 )=14]

Refine:

9 x  - 3 ( 3 x - 4 ) = 14

- 2 = 0

is false , therefore the system of equations has no solution

Answer A

hope this helps! 

Write 2.6 as a mixed fraction

Answers

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i got 2 3/5 as well . so that is the correct answer

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X^2=4x+12

Answers

steps are shown in the picture above
minus 4x+12 both sides
x^2-4x-12=0
what multipies to -12 and add to -4
-6 and 2
(x-6)(x+2)=0
set to zero
x-6=0
x=6

x+2=0
x=-2

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Do the data in the table represent a direct variation or an inverse variation? write an equation to model the data in the table. x 1 2 5 10

y 40 20 8 4

a. Direct variation; y=40x
b. Direct variation; y=(1/40)x
c. Inverse variation; xy=40
d. Inverse variation; xy=1/40

I feel so stupid for not knowing the answer, please explain it to me.

Answers

x =   1,  2, 5, 10
y = 40,20, 8,   4

a) y = 40x
y = 40(1) = 40   ; y = 40(2) = 80 ;
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b) y = (1/40)x ;
y = (1/40)1 = 1/40 ; y = (1/40)2 = 1/20 ;
y = (1/40)5 = 1/8   ; y =(1/40)10 = 1/4

c) xy = 40 ⇒ y = 40/x    
y = 40/1 = 40 ; y = 40/2 = 20
y = 40/5 = 8   ; y = 40/10 = 4

Inverse variation. Choice C. xy = 40  is the correct answer.