Last Year, a state university received 3,560 applications from boys. Of those applications, 35 Percent were from boys who lived in other states.Part A)How many applications did the university receive from boys who lived in other states?

Part B)Applications to the university from boys represented 40Percent of all applications. How many applications did the university receive In all?

I don't how to do part b so please help me and plz tell how you got your answer

Answers

Answer 1
Answer:

Part A) 1246 applications were received from other sides.

Part B) The university received a total of 8900 applications.

What is the percentage?

A percentage is a value per hundredth. Percentages can be converted into decimals and fractions by dividing the percentage value by a hundred.

Given, Last Year, a state university received 3,560 applications from boys. Of those applications, 35 Percent were from boys who lived in other states.

Assuming x no. of boys live in other states.

So, 35% of 3560 is x.

∴ (35/100)×3560 = x.

x = 0.35×3560.

x = 1246.

1246 applications were received from other sides.

Now, The university received 40% of the applications from boys, Assuming the total no. of applications to be y.

40% of y is 3560.

So, (40/100)y = 3560.

0.40y = 3560.

y = 3560/0.40.

y = 8900

The university received a total of 8900 applications.

Learn more about percentages here :

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Answer 2
Answer: a)10%=3560/100=356
5%=356/2=178
30%=356X3=1068
35%=1068+178=1246

b)10% of 40%=3560/4=890
100%890x10=8900(answer)

hope this helps

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49.4if f(x) - x-3/x and g(x) = 5x – 4, what is the domain of (fºg)(x)?
o {1x80}
* {1x^3}
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Answers

Answer:

domain is set of all real number except 4/5

Step-by-step explanation:

f(x)= (x-3)/(x)

g(x)=5x-4

Now we find (fºg)(x)

(fºg)(x)=f(g(x))

We plug in g(x) inside in f(x)

f(g(x))=f(5x-4)= ((5x-4)-3)/(5x-4)

Now simplify the numerator

f(g(x))=((5x-4)-3)/(5x-4)=(5x-7)/(5x-4)

To find out domain we set the denominator =0 and solve for x

5x-4=0

Add 4 on both sides

5x=4

Divide both sides by 5

x=(4)/(5)

So domain is set of all real number except 4/5

Answer:

Answer:

{x ∈ R ∣ x ≠ 4/5}

Step-by-step explanation:

At what value of x do the graphs of the equations below intersect? 2x − y = 6 5x + 10y = −10 −2 2

Answers

At x = -2, the graphs of equations 2x - y = 6 and 5x + 10y = -10 intersect at the point (-2,-2).

What is a graph?

A graph is a visual representation that shows the relationships between two or more items or values. It typically involves plotting points and connecting them to form a diagram.

To find the point of intersection of the graphs of equations 2x - y = 6 (i) and 5x + 10y = -10  (ii), we can follow these steps:

List out the points that satisfy each equation:

For equation (i):

  • When x=6, we have 2(6) - y = 6, which gives us y = 6. So point (6,6) lies on the graph of equation (i).

  • When x=0, we have 2(0) - y = 6, which gives us y = -6. So the point (0,-6) lies on the graph of equation (i).

  • When x=3, we have 2(3) - y = 6, which gives us y = 0. So point (3,0) lies on the graph of equation (i).

For equation (ii):

  • When x=0, we have 5(0) + 10y = -10, which gives us y = -1. So the point (0,-1) lies on the graph of equation (ii).

  • When x=2, we have 5(2) + 10y = -10, which gives us y = 0. So point (2,0) lies on the graph of equation (ii).

  • When x=4, we have 5(4) + 10y = -10, which gives us y = 1. So point (4,1) lies on the graph of equation (ii).

Plot the points on a graph and join them to get the graph of each equation.

Identify the point(s) of the intersection of the two graphs. From the graph, we see that the two graphs intersect at the point (-2,-2).

Therefore, we can conclude that at x = -2, the graphs of equations 2x - y = 6 and 5x + 10y = -10 intersect at the point (-2,-2).

Learn more about intersecting points of graphs here:

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Answer:

The solution to the equation is: (x,y) = (2,-2) If that helps

Step-by-step explanation:

// Solve equation [1] for the variable  y  

 

 [1]    y = 2x - 6

// Plug this in for variable  y  in equation [2]

  [2]    5x + 10•(2x-6) = -10

  [2]    25x = 50

// Solve equation [2] for the variable  x  

  [2]    25x = 50  

  [2]    x = 2  

// By now we know this much :

   x = 2

   y = 2x-6

// Use the  x  value to solve for  y  

   y = 2(2)-6 = -2  

Solution :

{x,y} = {2,-2}

What is 2(n+5)=-2 showing work

Answers

2(n + 5) = -2

First, our goal to this problem is to get the variable (n) and an unknown number on each side. To start off, we can divide both sides by 2.
n + 5 =  -(2)/(2)

Second, we can go ahead and cancel 2 out, which will replace it with a -1.
n + 1 = -1

Third, our next step will to be to subtract 5 from each side.
n = -1 - 5

Fourth, our last step is to simplify -1 - 5. This is quite simple. -1 - 5 = -6, so -6 is what the variable (n) equals. 
n = -6

Answer: \fbox {n = -6}
Simplify:
2n+10=-2

Subtract 10 from both sides
2n+10-10=-2-10
2n=-12

Divide both sides by 2
2n/2=-12/2

n=-6

Solve the linear inequality −6x+12>24

Answers

24∠-6x+12
-12       -12

12∠-6x
----  ---- 
-6     -6

x∠-2

Find the slope between (1,16) and (9,9).

Answers

Answer: slope = -7/8

Step-by-step explanation:

Slope = (y2-y1)/(x2-x1)

= (9-16)/(9-1)

= -7/8

Multiply. √3 ⋅ 2√2 ⋅ 5√8 ⋅ √18 Enter your answer, in simplest radical form, in the box.

Answers

\sqrt3\n2\sqrt2\n5\sqrt8=5√(4\cdot2)=5\sqrt4\cdot\sqrt2=5(2)\sqrt2=10\sqrt2\n√(18)=√(9\cdot2)=\sqrt9\cdot\sqrt2=3\sqrt2\n\n\sqrt3\cdot2\sqrt2\cdot5\sqrt8\cdot√(18)=\sqrt3\cdot2\sqrt2\cdot10\sqrt2\cdot3\sqrt2\n\n=(2\cdot10\cdot3)(\sqrt3\cdot\sqrt2\cdot\sqrt2\cdot\sqrt2)=60√(3\cdot2)\cdot√(2\cdot2)\n\n=60\sqrt6\cdot\sqrt4=60\sqrt6\cdot2=(60\cdot2)(\sqrt6)\n\n=\boxed{120\sqrt6}

Answer:

120√6

Step-by-step explanation:

Simplify the 5√8 to 2√2

simplify the √18 to 3√2

so it would be √3 * 2√2 * 5 * 2√2 * 3√2

when a square root of an expression is multiplied by itself:

√3 * 2 * 2* 5 * 2 * 3√2

so as we calculate it, 2 * 2* 5 * 2 * 3 = 120 and √2 * √3 = 6