Answer:
the answer is 2
Step-by-step explanation:
The problem we are having is the antiderivative of
\[e ^{0.2y}.\] We decided to split the problem into:
u = y
\[uv = e^{0.2y}\]
We just aren't sure where to go from here. Help?
Answer Choices
-100.3
-24.3
24.3
100.3
Answer:
D
Step-by-step explanation:
Given
y³ = 125 ( take the cube root of both sides )
=
y = 5 → D
add and simplify 9/16=1/2=?
Dogs 5
Rabbits 1
Guinea Pigs 3
Which of the following plots represents the data in the table?
A) A line with 4 tick marks labeled Cat, Dog, Rabbit, and Guinea Pig. Cat has 3 crosses, Dog has 5 crosses, Rabbit has 1 cross, and Guinea Pig has 3 crosses. The line is labeled Number of Pets, and title of graph is Pet Owners.
B) A line with 4 tick marks labeled Cat, Dog, Rabbit, and Guinea Pig. Cat has 3 crosses, Dog has 5 crosses, Rabbit has 5 crosses, and Guinea Pig has 3 crosses. The line is labeled Number of Pets, and title of graph is Pet Owners.
C) A line with 4 tick marks labeled Cat, Dog, Rabbit, and Guinea Pig. Cat has 3 crosses, Dog has 1 cross, Rabbit has 1 cross, and Guinea Pig has 3 crosses. The line is labeled Number of Pets, and title of graph is Pet Owners.
D) A line with 4 tick marks labeled Cat, Dog, Rabbit, and Guinea Pig. Cat has 2 crosses, Dog has 4 crosses, Rabbit has 0 cross, and Guinea Pig has 2 crosses. The line is labeled Number of Pets, and title of graph is Pet Owners.
Option “A” is correct, because the number of crosses against the pets is equal to its actual quantity given in the question.
So
Cats = 3 = xxx
Dogs = 5 = xxxxx
Rabbit = 1 = x
Guinea Pigs = 3 = xxx
Answer:
a
Step-by-step explanation: