By completing the square, the second orderpolynomial in vertexform f(x) = (x + 3)² - 6 is equivalent to the polynomial in standardform f(x) = x² + 6 · x + 3. (Correct choice: B)
In this question we must change the form of the second orderpolynomial from standardform into vertexform. A common method consists in completing the square, that is, to transform part of the polynomial into a perfect squaretrinomial. Now we proceed to find the vertexform of the expression:
1) x² + 6 · x + 3 Given
2) x² + 6 · x + 9 - 6 Modulative property/Existence of additive inverse/Definition of addition
3) (x + 3)² - 6 Associative property/Perfect square trinomial/Result
By completing the square, the second orderpolynomial in vertexform f(x) = (x + 3)² - 6 is equivalent to the polynomial in standardform f(x) = x² + 6 · x + 3. (Correct choice: B)
To learn more on second order polynomials in vertex form: brainly.com/question/20333425
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Answer:
B. f(x) = (x + 3)2 − 6
Step-by-step explanation:
I just did this for "completing the square". Hope this helped!
4x6
4x18
8x6
8x18
Answer: 4x^18
Step-by-step explanation: I did it on edge already.
Step 2: x = 30 – 5
Step 3: x = 25
Part A: Is Charlie's solution correct or incorrect? If the solution is incorrect, explain why it is incorrect and show the correct steps to solve the equation.
Part B: How many solutions will this equation have?
Answer:
The additive inverse of 4x is -4x