How does friction slow things down?

Answers

Answer 1

Answer: Friction slows things down because the force that is created through the interaction between two objects begins to decrease the acceleration and velocity of the object. Therefore, the object begins to slow down.

Answer 2

Answer: friction slows things down because the tiny rough bumps on all surfaces hook on each other and slow down the object and produce heat

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If it takes 726 W of power to move a mass 36 m and 14 seconds what is the mass

Answers

From that information, I can tell that the force pushing on the mass
averaged (282 and 1/3) newtons during those 24 seconds.

But the information doesn't nail down what the mass must be.
I think it would if we only knew something about the friction.
Either tell us how much friction there is, or tell us that there's
none, and I think I could find the mass.

power = work / time
work = force * displacement
force = mass * gravity

so:

power = (mass * gravity * displacement) / time
726 = (mass * 9.81 * 36 ) / 14
726 * 14 = mass * 9.81 * 36
10164 = mass * 353.16
mass = 10164 / 353.16

mass = 28.78 kg

Which of the following statements accurately describes the properties of gases? A. Gases expand very easily due to a property called compressibility.

B. A change in the pressure of a gas results in a more significant change in volume than it would in a liquid.

C. Applying an external force to an enclosed volume of air will allow the air to expand and the volume to decrease.

D. When the mass of gases remains constant, the gases have low compressibility and low expansibility.

Answers

A change in the pressure of a gas results in a more significant change in volume than it would in a liquid. is the statement that accurately describes the property of gas. Gas only depends on how you store it. the bigger the space the wider gas can expand, the smaller the space, the more compress the gas can become.

Answer: B. a change in a pressure of a gas results in a more significant change in volume than it would in a liquid

Explanation: PF

Suppose a yo-yo has a center shaft that has a 0.230 cm radius and that its string is being pulled.(a) If the string is stationary and the yo-yo accelerates away from it at a rate of 1.80 m/s2, what is the angular acceleration of the yo-yo in rad/s2? rad/s2.
(b) What is the angular velocity in rad/s after 0.750 s if it starts from rest? rad/s.
(c) The outside radius of the yo-yo is 3.10 cm.What is the tangential acceleration in m/s2 of a point on its edge? m/s2

Answers

Answer:

Part a)

$\alpha = 782.6 rad/s^2$

Part B)

$\omega = 587 rad/s$

Part c)

$a_t = 24.3 m/s^2$

Explanation:

Part a)

As we know that

$a = R \alpha$

so we will have

$a = 1.80 m/s^2$

$R = 0.230 cm$

$\alpha = (a)/(R)$

$\alpha = (1.80)/(0.230 * 10^(-2))$

$\alpha = 782.6 rad/s^2$

Part B)

Angular speed of the yo-yo

$\omega = \alpha t$

so we have

$\omega = 782.6 * 0.750$

$\omega = 587 rad/s$

Part c)

Tangential acceleration is given as

$a_t = R \alpha$

$a_t = (3.10 * 10^(-2))(782.6)$

$a_t = 24.3 m/s^2$

The rock beneath the continents is made of _____. A.) granite
B.) basalt
C.) obsidian
D.) pumice

Answers

The correct answer is: (A. Granite <------

Hope i helped!:)

The answer would be A -- Granite.

what is the free-fall acceleration at the surface of the jupiter?you may have submitted the value posted in the internet. recall newton's law of universal gravitation and use the values for jupiter's mass and mean radius from the textbook.no credit lost. try again.

Answers

Answer:

The formula for acceleration due to gravity at the surface of a celestial body is:

a = (G * M) / r^2

Where:

G (the gravitational constant) is approximately 6.67430 x 10^-11 m^3 kg^-1 s^-2.

M (the mass of Jupiter) is approximately 1.898 x 10^27 kilograms.

r (the mean radius of Jupiter) is approximately 71,492,000 meters.

Now, let's calculate it:

a = (6.67430 x 10^-11 m^3 kg^-1 s^-2 * 1.898 x 10^27 kg) / (71,492,000 meters)^2

a ≈ 24.79 m/s^2

So, the free-fall acceleration at the surface of Jupiter is approximately 24.79 m/s^2.

Final answer:

The free-fall acceleration on the surface of Jupiter (g) is calculated by using Newton's Universal Law of Gravitation (g = G * M / r^2), where G is the gravitational constant, M is the mass of Jupiter and r is the radius of Jupiter.

Explanation:

To calculate the acceleration due to gravity at the surface of Jupiter, we can use Newton's Universal Law of Gravitation. It states that the force of gravity is equal to the gravitational constant (G) times the mass of the body (in this case, Jupiter) divided by the radius of the body squared. The formula can be expressed as F = G * (M * m / r^2), where F is the force of gravity, G is the gravitational constant, M is the mass of the larger body (Jupiter), m is the mass of the smaller body (object in question), and r is the distance between the centers of the two bodies - which is the radius of Jupiter when the object is on its surface.

The formula to find the acceleration due to gravity (g) on the surface of Jupiter is found by setting the weight of an object (F = m*g) equal to the gravity force (F = G * (M * m / r^2)) leading to the cancellation of the mass of the object (m). That results in g = G * M / r^2. This means that the acceleration due to gravity on the surface of Jupiter depends on the mass of Jupiter and the radius of Jupiter, and not on the mass of the object.

Learn more about Jupiter's Free-fall Acceleration here:

brainly.com/question/13962752

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A carousel is spinning at a speed of 100 cm/s, with the outermost horse at a distance 5 m from the center.Calculate the inward force on the outermost horse, if it weighs 1.5 kg.

A) 3 x 10-3 N
B) 3 x 10-2 N
C) 3 x 10-1 N
D) 3 x 10 N

Answers

The speed is 100/100=1 meter per second, so acceleration is 1^2/5=.2. Then, the net force is 0.2*1.5 kg = 0.3 N, or 3*10^-1 N.

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