An increase in thermal energy causes molecules to move more rapidly and vibrate more quickly. Higher temperatures affect the distribution of kinetic energies and can cause phase changes.
When thermal energy increases, molecules gain more kinetic energy and therefore move more rapidly. This increased kinetic energy causes molecules to vibrate more quickly. As a result, the temperature of the substance increases. Higher temperatures also affect the distribution of kinetic energies among the molecules in a substance. At higher temperatures, more molecules have the necessary kinetic energy to escape from a liquid to the gas phase.
Additionally, increasing thermal energy can cause phase changes in a substance, such as melting or vaporization, where additional energy is used to loosen bonds between molecules or atoms without changing the temperature. Thus, adding thermal energy can lead to the melting or vaporization of a substance.
#SPJ6
The pitch is higher as it approaches and then becomes lower the moment it passes.
Answer:
4.281 kgm/s upward
Explanation:
Impulse:This can be defined product of force and time. The S.I unit of impulse is Ns.
From Newton's second law of motion,
Impulse = Change in momentum.
I = mΔv....................... Equation 1.
Where m = mass of the ball, Δv = change in velocity of the ball
and Δv = v -u
Where u = velocity of the ball before it hit the floor, v = velocity of the ball after if hit the floor
I = m(v-u) -------------- Equation 2
But
the initial kinetic energy of the ball = potential energy at the initial height (1.2 m above)
1/2mu² = mgh₁
Where h₁ = initial height. or height of the ball before collision
making u the subject of the equation,
u = √(2gh₁)........................ Equation 3
Where h₁ = 1.2 m g = 9.81 m/s²
Substitute into equation 3
u = √(2×1.2×9.81)
u =√(23.544)
u = -4.852 m/s.
Note: u is negative because the ball was moving downward at the first instance.
Similarly,
v = √(2gh₂)............................. Equation 3
h₂ = height of the ball after collision
Given: h₂ = 0.7 m, g = 9.81 m/s²
Substitute into equation
v = √(2×9.81×0.7)
v = √13.734
v = 3.71 m/s.
Also given: m = 0.5 kg,
Substituting into equation 2
I = 0.5(3.71-(4.852)
I = 0.5(8.562)
I = 4.281 kgm/s. Upward.
Thus the impulse = 4.281 kgm/s upward