Answer:
P = 62° Q = 28°
Step-by-step explanation:
Let x = measure of angle Q
then y = measure of angle P
Now x + y = 90 and 2x + 6 = y
Substituting 2x + 6 from the second equation in for y in the first equation, we get x + 2x + 6 = 90 since the two angles are complementary.
3x + 6 = 90
3x = 84
x = 28
y = 2(28) + 6 = 56 + 6 = 62
Check: 28 + 62 = 90
To find the measures of complementary angles P and Q, we set up a system of equations based on the problem's information, solve for one variable, then substitute that variable's value into the other equation. After solving, we find that the measure of angle P is 62°, and the measure of angle Q is 28°.
Let's denote the measure of angle Q as 'q'. Therefore, the measure of angle P can be expressed as '2q + 6'. Now, we can set up two equations based on the information given:
Solving the first equation gives us 3q + 6 = 90. Subtract 6 from each side of the equation to get 3q = 84. Divide each side by 3 to solve for 'q', and we find that q = 28°. Substituting q = 28° into equation 2, we find that P = 2*28 + 6 = 62°. So, angle P is 62° and angle Q is 28°.
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A)6
B)5
C)4
mm2
surface area of a rectangular prism with a base length of 70 mm^2, perimeter of the base is 50 mm. The height of the prism is 9 mm. let a= base length, b = base width, c = height=9. a*b= 70. a+b+9=50, or a+b=41, now bc+ca= c(a+b)=9*41=369 so suface area= 2(ab+bc+ca)= 2(70+369)=878 mm^2
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= 3
why is this incorrect?
Let x represent , then you can rewrite the expression as 3x - x.
3x - x = 2x. Now replace "x" with and you get 2.
The reason 3 is incorrect is because you are supposed to perform the operation (+, -, x, ÷) with the coefficients, not with the variable or radical.
Algebraically, you have to factor the square root of 7 to see why you're wrong:
Conceptually, think that any object - say an apple - represents the square root of seven.
So, you have three apples, and you take away one apple. You have two apples remaining, i.e.