Answer:
cool?
Step-by-step explanation:
a) an = 6an-1, a0 = 2
b) an = −2an-1, a0 = −1
c) an = an-1 – an-2, a0 = 2, a1 = −1
a) The first five terms of the sequence are 2, 12, 72, 432, 2592.
b) The first five terms of the sequence are -1, 2, -4, 8, -16.
c) The first five terms of the sequence are 2, -1, -3, -2, 1.
To find the first five terms of the sequence defined by each of these recurrence relations and initial conditions, we will use the given recurrence relation and initial conditions to find the next terms in the sequence.
a) an = 6an-1, a0 = 2
The first term is given as a0 = 2. We will use the recurrence relation to find the next terms.
a1 = 6a0 = 6(2) = 12
a2 = 6a1 = 6(12) = 72
a3 = 6a2 = 6(72) = 432
a4 = 6a3 = 6(432) = 2592
So, the first five terms of the sequence are 2, 12, 72, 432, 2592.
b) an = −2an-1, a0 = −1
The first term is given as a0 = -1. We will use the recurrence relation to find the next terms.
a1 = -2a0 = -2(-1) = 2
a2 = -2a1 = -2(2) = -4
a3 = -2a2 = -2(-4) = 8
a4 = -2a3 = -2(8) = -16
So, the first five terms of the sequence are -1, 2, -4, 8, -16.
c) an = an-1 – an-2, a0 = 2, a1 = −1
The first two terms are given as a0 = 2 and a1 = -1. We will use the recurrence relation to find the next terms.
a2 = a1 - a0 = -1 - 2 = -3
a3 = a2 - a1 = -3 - (-1) = -2
a4 = a3 - a2 = -2 - (-3) = 1
So, the first five terms of the sequence are 2, -1, -3, -2, 1.
Learn more about Recurrence
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x²(x + 4) + 5(x + 4)
Factoring (also called factorization) is the reserve operation of multiplication. When we factor (or factorize) a polynomial, we write it as a product of its factors.
Grouping is one of the factoring methods. Other methods such as isolating common factors and identities.
Steps for grouping:
Let’s start.
We can also group the terms as follows.
We will get the same results from the two ways above. Let's see.
Thus the part which shows one way to determine the factors of x³ + 4x² + 5x + 20 by grouping is
Keywords: which shows, one way, to determine, the factors of x³ + 4x² + 5x + 20, by grouping, common factor, polynomial, identities
The correct option is that is that shows one way to determine the factors of .
Further explanation:
Factors are the numbers if we multiply them we get the original number.
Factorization is finding the numbers if we multiply them we get the original number.
Prime factorization is finding the numbers if we multiply them we get the original number.
Given:
The polynomial is .
The options are,
A. .
B. .
C. .
D.
Explanation:
Consider the polynomial as .
Steps involve in finding the factors of are as follows,
First we have to make the groups of the terms as,
Now factorize the above 2 groups.
The factors of .
Option A is not correct as the first common factor is from group one but it not the highest common factor.
is correct as the factors are same as the factors of the polynomial.
Option C is not correct as the factors are not same as the factors of the polynomial.
Option D is not correct as the factors are not same as the factors of the polynomial.
Learn more:
1. Learn more about the polynomial brainly.com/question/12996944
2. Learn more about logarithm model brainly.com/question/13005829
3. Learn more about the product of binomial and trinomial brainly.com/question/1394854
Answer details:
Grade: High school
Subject: Mathematics
Chapter: Polynomials
Keywords: factor, factorization, polynomial, quadratic, cubic, greatest common factor, groups, multiplication, product, identities, common factor, expression, terms, grouping.
Answer:
Step-by-step explanation:
To evaluate the expression 2% 0f 6700, we can follow the steps;
2% = 2/100
6700 = 67(100)
2% of 6700 = 2/100 * 67(100)
The 10 at the numerator will cancel out that at the denominator
2/100 * 67(100) = 2(67)
2(67) = 134
Answer:
Write 2% as the ratio 2/100. Write the equivalent ratio_?_ . (100)(67)= 6700, so (2)(67)=134
6700
Step-by-step explanation: Just did it on edg 2020. IF THIS HELPS IT IS C.
Answer:
a = 25m^2
b = 5m
d = 35.73 m^2
c = 7.94m
Step-by-step explanation:
First, remember that the area of a square of side length L is:
A = L^2
And for a triangle rectangle with catheti a and b, and hypotenuse H, we have the relation:
H^2 = a^2 + b^2 (Phytagorean's theorem)
Ok, let's look at the left image, we have a green triangle rectangle.
The bottom cathetus has a length equal to the side length of a square with area of 16m^2
Then the side length of that square (and the cathetus) is:
L^2 = 16m^2
L = √(16m^2) = 4m
The left cathetus has a length equal to the side length of a square of area = 9m^2
Then the side length of that cathetus is:
K^2 = 9m^2
K = √(9m^) = 3m
Then the catheti of the green triangle rectangle are:
4m and 3m
Then the hypotenuse of this triangle (b) is:
b^2 = (4m)^2 + (3m)^2
b^2 = 16m^2 + 9m^2 = 25m^2
b = √(25m^2) = 5m
And b is the side length of the red square, then the area of that square is:
a = b^2 = 25m^2
Now let's go to the other image.
Here we have an hypotenuse of side length H, such that:
H^2 = 144m^2
And we have a cathetus (the one adjacent to the green triangle) of side length L such that:
L^2 = 81m^2
The other cathetus will have a sidelength c, such that:
c^2 = area of the purple square
By the Pythagorean's theorem we have:
144m^2 = 81m^2 + c^2
144m^2 = 81m^2 + c^2
144m^2 - 81m^2 = c^2
63m^2 = c^2
(√63m^2) = c = 7.94m
And the area of a triangle rectangle is equal to the product between the catheti divided by two.
We know that one cathetus is equal to c = 7.94m
And the other on is equal to the square root of 81m^2
√(81m^2) = 9m
then the area of the triangle is:
d = (7.94m)*(9m)/2 = 35.73 m^2