2 images attatched below
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distance : time = 20 km : 1/2 hour = 40 km/hour
B. 1. what quantities can be identified in the graph?
2. explain the meaning of the horizontal lines in the graph.
3. calculate agni's velocity during the race.
4. calculate the speed reached by agni at the end of the race.
on independence day, there was a bicycle race organized in a neighborhood. an observer took notes on the progress of one participant, named agni. who finally won the race... the collected data is shown in " graph of agni's bicycle track " as shown below
One oscillator in the wave takes
0.115 s to go from the lowest point
in its motion to the highest point.
Find the frequency of the wave.
(Unit = Hz)
Answer:
The frequency of wave is 4.34 Hz.
Explanation:
We know the relation:
λ = = × ........................................1
where,
λ= wavelength
v= velocity of wave
T= Period of wave
By the definition of period T, you are given that HALF of T is 0.115 s, so
T = 2 × (0.115 s)
= 0.23 s
Then,
λ = v × T
= (7.33 m/s) × (0.23 s)
≅ 1.686 m
Now for frequency, return to equation 1,
=
=
= 4.34
The frequency of the wave is calculated as 4.34 Hz.
Answer:
0.230
Explanation:
That's the answer, the one above isn't, I got this answer correct on acellus
c. What is the instantaneous velocity of the rock just before it hit the ground?
d.Find the rock's displacement for the 10 seconds.
c. -98 m/s
The motion of the rock is a uniformly accelerated motion (free fall) with constant acceleration (negative since it is downward). Therefore, we can find its velocity using the following suvat equation
where
v is the final velocity
u is the initial velocity
g is the acceleration of gravity
t is the time
For the rock in the problem,
u = 0
So, its velocity at t = 10 s is
where the negative sign indicates that the velocity points downward.
d. -490 m
Since the motion is at constant acceleration, we can use another suvat equation:
where
s is the displacement
u is the initial velocity
g is the acceleration of gravity
t is the time
Substituting:
u = 0
t = 10 s
We find the rock's displacement:
where the negative sign means the displacement is downward.
The angular velocity of a clocks second hand, its minute hand, and its hour hand are 0.1047rad/s, 1.745 × 10⁻³rad/s and 1.454 × 10⁻⁴rad/s respectively.
Time period for second hand;
Time period for minute hand;
Time period for hour hand;
Now, we use the relation between angular speed and time period:
Where ω is the angular velocity and T is the time period in seconds.
For Second hand
For Minute hand
For Hour hand
Therefore, the angular velocity of a clocks second hand, its minute hand, and its hour hand are 0.1047rad/s, 1.745 × 10⁻³rad/s and 1.454 × 10⁻⁴rad/s respectively.
Learn more: brainly.com/question/8711708
Second hand:
1 rev per minute = (2π radians/minute) x (1 min/60sec) = π/30 rad/sec
Minute hand:
1 rev per hour = (2π radians/hour) x (1 hr/3600 sec) = π/1800 rad/sec
Hour hand:
1 rev per 12 hours = (2π rad/12 hr) x (1 hr/3600 sec) = π/21,600 rad/sec
As long as the clock is in good working order, and the hands are turning steadily at their normal rate, there is no angular acceleration.