b. How high did the arrow go?
c. How long is the arrow in the air?
a) The velocity of the arrow at its peak is zero
b) The maximum height of the arrow is 31.9 m
c) The time of flight is 5.10 s
Explanation:
a)
The motion of the arrow fired straight upward into the air is a uniformly accelerated motion, with constant acceleration (acceleration of gravity) towards the ground.
The initial velocity of the arrow when it is fired is upward: since the acceleration is downward, this means that as the arrow moves upward, its velocity decreases in magnitude.
Eventually, at some point, the velocity of the arrow will become zero, and then it will change direction (downward) and will start increasing in magnitude. The moment when the velocity raches zero corresponds to the peak of the trajectory of the arrow: therefore, at the peak the velocity is zero.
b)
Since the motion of the arrow is a uniformly accelerated motion, we can use the following suvat equation:
where
v is the final velocity
u is the initial velocity
a is the acceleration
s is the displacement
For the arrow, we have:
u = 25 m/s
v = 0 (when the arrow reaches the peak)
(negative because downward)
s is the maximum height reached by the arrow
And solving for s,
c)
In order to find the time it takes for the arrow to reach the maximum height, we use the following suvat equation:
where here we have:
v = 0 is the final velocity at the peak
u = 25 m/s
And solving for t,
This is the time the arrow takes to reach the top of the trajectory: therefore, the total time of flight is twice this value,
Learn more about accelerated motion:
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Answer:
g = 4.7 × m/
Explanation:
Given that the mass of the satellite = 700 kg, and 10,000 m above the earth;s surface.
From Newton's second law,
F = mg ............... 1
From Newton's gravitation law,
F = .................. 2
Where: F is the force, G is the gravitational constant, M is the mass of the first body, m is the mass of the second body, g is the gravitational force and r is the distance between the centers of the two bodies.
Equate 1 and 2 to have,
mg =
⇒ g =
But; G = 6.67 × N , M = 700 Kg, r = 10000 m
Thus,
g =
=
= 4.669 × m/
The force of gravity on the satellite is 4.7 × m/.
The force of gravity on a 700kg satellite 10km above the Earth's surface can be calculated using the equation F = mg.
The force of gravity on an object is given by the equation F = mg, where F is the force of gravity, m is the mass of the object, and g is the acceleration due to gravity.
On Earth's surface, the acceleration due to gravity is approximately 9.8 m/s^2. However, as the satellite is 10 km above the Earth's surface, the force of gravity will be slightly less than that.
To calculate the force of gravity on the satellite, we can use the equation F = mg. Substituting the mass of the satellite (700 kg) and the acceleration due to gravity (9.8 m/s^2 - (9.8 m/s^2 * (10 km/ 6371 km))), we can find the force of gravity.
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Answer:
14 kg
Explanation:
Momentum = mass × velocity
p = mv
100 kg m/s = m (7.0 m/s)
m ≈ 14 kg
10–3 m
10–6 m
10–9 m
10–12 m
Based on scientific information and records, the magnitude of a nanometer is equal to: C. 10⁻⁹ m.
Measurement refers to a process through which the size, magnitude or other physical quantities associated with an object is taken, especially for the purpose of a scientific research (experiment).
In the metric system, a nanometer can be defined as a measure of length such as:
In conclusion, a nanometer is one billionth (10⁻⁹ m) of a meter.
Read more on a nanometer here: brainly.com/question/5753030
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The magnitude would be 10-9m