MATHEMATICS COLLEGE

An airplane makes a 2,748-mile flight in 6 hours. What is the airplane's average rate of speed in miles per hour?

Answers

Answer 1

Answer:

Answer:

speed=16,480 miles per hour or 16,480/hour.

Step-by-step explanation:

Distance=speed ×time

Related Questions

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What is the answer to a
Solve the quadratic equation by factoring. x^2 - 4x - 12 = 0
Assume that male and female births are equally likely and that the birth of any child does not affect the probability of the gender of any other children find the probability of at most three boys in ten births
Geometry proof help please

Hey can you please help me posted picture of question

Answers

Shifting to right means subtracting the number from x.

So, shifting to right by 9 units means, subtracting 9 from x.

G(x) = F(x - 9)

G(x) = |x - 9|

So, option D is the correct answer

Guided Practice1. A manufacturer gets a shipment of 600 batteries of which 50 are
defective. The quality control manager tests a random sample of
30 batteries in each shipment. Simulate the test by generating random
numbers between 1 and 600. How well does your sample represent the
shipment? Explain. (Explore Activities 1 and 2)

Answers

Answer:

18.33

Step-by-step explanation:

600 -50 ÷ 30

550 ÷30 = 18.333

Identify the initial value, a, and base, b, of the function f(x)=ab^x if its graph passes through the points (0, 4) and (1, 20)

Answers

Answer:

a = 4, b = 5

Step-by-step explanation:

Given the exponential function

f(x) = a $b^(x)$

Use the given points to find a and b

Using (0, 4 ) , then

4 = a $b^(0)$ ( $b^(0)$ = 1 ) , thus

a = 4 , so

f(x) = 4 $b^(x)$

Using (1, 20 ) , then

20 = 4b ( divide both sides by 4 )

b = 5

A particular concentration of a chemical found in polluted water has been found to be lethal to 40% of the crayfish that are exposed to the concentration for 24 hours. 22 crayfish are placed in a tank containing this concentration of chemical in the water. (a) What is the probability that 13 or 17 survive?
(b) What is the probability that at least 17 survive?
(c) What is the probability that at most 16 survive?
(d) What number of crayfish are expected to survive?
(e) What is the variance in the number of crayfish that are expected to survive? No actual crayfish were harmed in the making of this question.

Answers

Answer:

a) $P(X=13)=(24C13)(0.4)^(13) (1-0.4)^(24-13)=0.0608$

$P(X=17)=(24C17)(0.4)^(17) (1-0.4)^(24-17)=0.0017$

$P(X=13 U X=17) = 0.0608+0.0017=0.0624$

b) $P(X \geq 17)=0.000427$

c) $P(X \geq 16)= 1-0.000427=0.9996$

d) $E(X)= np = 22*0.4=8.8$

e) $Var(X) = np(1-p)= 22*0.4*(1-0,4)=5.28$

Step-by-step explanation:

1) Previous concepts

The binomial distribution is a "DISCRETE probability distribution that summarizes the probability that a value will take one of two independent values under a given set of parameters. The assumptions for the binomial distribution are that there is only one outcome for each trial, each trial has the same probability of success, and each trial is mutually exclusive, or independent of each other".

2) Solution to the problem

Let X the random variable of interest, on this case we now that:

$X \sim Binom(n=24, p=0.4)$

The probability mass function for the Binomial distribution is given as:

$P(X)=(nCx)(p)^x (1-p)^(n-x)$

Where (nCx) means combinatory and it's given by this formula:

$nCx=(n!)/((n-x)! x!)$

3) Part a

$P(X=13)=(22C13)(0.4)^(13) (1-0.4)^(22-13)=0.0336$

$P(X=17)=(22C17)(0.4)^(17) (1-0.4)^(22-17)=0.00035$

$P(X=13 U X=17) = 0.0336+0.00035=0.0340$

4) Part b

$P(X \geq 17)=P(X=17)+P(X=18)+P(X=19)+P(X=20)+P(X=21)+P(X=22)$

$P(X=17)=(22C17)(0.4)^(17) (1-0.4)^(22-17)=0.00035$

$P(X=18)=(22C18)(0.4)^(18) (1-0.4)^(22-18)=0.0000651$

$P(X=19)=(22C19)(0.4)^(19) (1-0.4)^(22-19)=0.00000914$

$P(X=20)=(22C20)(0.4)^(20) (1-0.4)^(22-20)=0.000000914$

$P(X=21)=(22C21)(0.4)^(21) (1-0.4)^(22-21)=5.81x10^(-8)$

$P(X=22)=(22C22)(0.4)^(22) (1-0.4)^(22-22)=1.76x10^(-9)$

$P(X \geq 17)=0.000427$

5) Part c

$P(X \leq 16)=1-P(X>16)=1-P(X\geq 17) = 1-[P(X=17)+P(X=18)+P(X=19)+P(X=20)+P(X=21)+P(X=22)]$

$P(X \geq 16)= 1-0.000427=0.9996$

6) Part d

The expected value is:

$E(X)= np = 22*0.4=8.8$

7) Part e

The variance is given by:

$Var(X) = np(1-p)= 22*0.4*(1-0,4)=5.28$

Carol drew an isosceles triangle that has an angle that measures 62°. Which could be the measures of the other two angles in Carol’s triangle?A. 62° and 62°
B. 56° and 56°
C. 28° and 90°
D. 56° and 62°

Answers

Answer: the answer is B

Step-by-step explanation:

Answer:

56 and 62

Step-by-step explanation:

Find the first, fourth, and tenth terms of the arithmetic sequence described by the given rule.A(n) = 1 + (n – 1)(–5.7)

1, –21.8, –56

–5.7, –21.8, –51.3

1, –16.1, –50.3

0, –17.1, –51.3

If someone answers this, i'd like if someone could help me to know how to solve it too, please and thank you!

Answers

1, - 16.1, - 50.3 ← third on list

To find the required terms, substitute n = 1, 4, 10 into the rule and evaluate

A(1) = 1 + (1 - 1)(- 5.7) = 1 + 0 = 1

A(4) = 1 + (4 - 1)(- 5.7 ) = 1 + (3 × - 5.7 ) = 1 - 17.1 = - 16.1

A(10) = 1 + (10 - 1 )(- 5.7) = 1 + (9 × - 5.7) = 1 - 51.3 = - 50.3

$\bf \stackrel{A(n)=1+(n-1)(-5.7)}{ \begin{array}{ll} n\qquad \qquad &A(n)\n \cline{1-2} 1&1+(1-1)(-5.7)\n &1+0\n &1\n\n 4&1+(4-1)(-5.7)\n &1+(3)(-5.7)\n &1-17.1\n &-16.1\n\n 10&1+(10-1)(-5.7)\n &1+(9)(-5.7)\n &1-51.3\n &-50.3 \end{array} }$

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