Hence , the sum is .
In mathematics, a polynomial is an expression consisting of indeterminates (also called variables) and coefficients, that involves only the operations of addition, subtraction, multiplication, and non-negative integer exponentiation of variables.
Given , we need to add and .
So, we can write it as :
Writing like terms together:
Hence , the answer is .
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Answer:f
(x)=x, g(x)=x3−1f(x)=x4+x3−11x2−5x+30, g(x)=2x−2f(x)=x2, g(x)=7x−1
in short ways the answer is 7x−1
The actual number of jelly beans is 300.
What is the percent error of Li’s guess?
Answer:
15
Step-by-step explanation:
345-300 X 100 = 15%
300
Answer:
Percent error =
15%
Li’s guess was off by
15%.
Step-by-step explanation:
TTM </3
1 though 5
Answer:
5/8,-5√2,{(2x+3)(x-5)}
Step-by-step explanation:
1) 5x-10/8x-16
=5(x-2)/8(x-2)
=5/8
2) √32-3√18
=4√2-3√18
=4√2-9√2
=(4-9)√2
= -5√2
4) 2x^2-7x-15
=2x^2+3x-10x-15
=(2x+3),(x-5)
Answer:
23.7m
Step-by-step explanation:
Given parameters:
Time taken = 2.2s
Acceleration due to gravity = 10m/s
Unknown:
Depth of the well = ?
Solution:
To solve this problem, we simply apply one of the motion equations;
S = ut + gt²
where S = depth of the well
u = initial velocity
t = time taken
g = acceleration due to gravity
Input the parameters and solve for S;
Note initial velocity = 0;
S = x 9.8 x 2.2²
S = 23.7m
2. Regular pentagon PENTA has side lengths that are 9 meters long. To the nearest square meter, find the area of the pentagon.
Area of pentagon PENTA = _____square centimeter
1) Trapezoid BEAR with bases 11.5 and 6.5 and height 8.5, all in cm.
2) Regular pentagon PENTA with side lengths 9 m
The area of each figure, rounded to the nearest integer
1) The area of a trapezoid is given by
... A = (1/2)(b1 +b2)h
... A = (1/2)(11.5 +6.5)·(8.5) = 76.5 ≈ 77
The area of BEAR is about 77 cm².
2) The conventional formula for the area of a regular polygon makes use of its perimeter and the length of the apothem. For an n-sided polygon with side length s, the perimeter is p = n·s. The length of the apothem is found using trigonometry to be a = (s/2)/tan(180°/n). Then the area is ...
... A = (1/2)ap
... A = (1/2)(s/(2tan(180°/n)))(ns)
... A = (n/4)s²/tan(180°/n)
We have a polygon with s=9 and n=5, so its area is
... A = (5/4)·9²/tan(36°) ≈ 139.36
The area of PENTA is about 139 m².
Answer:139 cm squared
The area of a trapezoid is given by
... A = (1/2)(b1 +b2)h
... A = (1/2)(11.5 +6.5)·(8.5) = 76.5 ≈ 77
The area of BEAR is about 77 cm².
The conventional formula for the area of a regular polygon makes use of its perimeter and the length of the apothem. For an n-sided polygon with side length s, the perimeter is p = n·s. The length of the apothem is found using trigonometry to be a = (s/2)/tan(180°/n). Then the area is ...
... A = (1/2)ap
... A = (1/2)(s/(2tan(180°/n)))(ns)
... A = (n/4)s²/tan(180°/n)
We have a polygon with s=9 and n=5, so its area is
... A = (5/4)·9²/tan(36°) ≈ 139.36
The area of PENTA is about 139 m².
∠ABF and ∠CBE are vertical angles
3x + 25 + 7x - 19 = 10x - 6
Set them equal to each other
∠ABF = ∠CBE
6x + 26 = 10x - 6
Isolate the x. Subtract 6x from both sides and add 6 to both sides
6x (-6x) + 26 (+6) = 10x (-6x) - 6 (+6)
26 + 6 = 10x - 6x
Simplify
32 = 4x
Divide 4 from both sides
32/4 = 4x/4
x = 32/4
x = 8
m∠ABF = 6x + 26
Plug in 8 for x
6(8) + 26 = m∠ABF
48 + 26 = m∠ABF
m∠ABF = 74°
74° is your answer for m∠F
hope this helps