MATHEMATICS COLLEGE

For one child, a childcare facility charges $350 per month for preschool and $5.00 per hour for each additional hour for after-school care. The function below can be used to determine f(h), the monthly fee for after-school care and preschool, where h represents the number of hours spent in after-school care.f(h) = 350 + 5h

If the total monthly bill for one child was $750, what was the total number of hours the child spent in after-school care?

A.100
B.90
C.88
D.80

Answers

Answer 1

Answer:

Answer:

D.) 80

Step-by-step explanation:

750 - 350 = 400

400/5 = 80

80 hours

Hopefully this helps you :)

pls mark brainlest ;)

Answer 2

Answer:

Answer:

D-80

Step-by-step explanation:

750-350=400

400/5=80

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In the 2020 Super Bowl, San Francisco lost by 11 points. Develop a playbook for the team to use to win the game if there were 5 minutes on the clock.

$√(2) ^( √(7) )$ use a calculator to find an approximation for each power. give the maximum number of decimal places that your calculator displaysround this value to ,7 decimal places,.

Answers

We are given the following expression

$\sqrt[]{2}^{\sqrt[]{7}}$

Here the base is √2 and its power (exponent) is √7

The value of this expression can easily be calculated using any scientific calculator.

The maximum number of decimal places depends upon the type of calculator you use.

$\sqrt[]{2}^{\sqrt[]{7}}=2.50164253682$

Let us round this value to 7 decimal places.

$\sqrt[]{2}^{\sqrt[]{7}}=2.5016425$

A local department store sells carpet in 4 sizes . Each carpet comes in 3 different qualities. One of the size come in 5 colors . The other sizes come in 3 colors . How many choices of carpet are there?

Answers

The total number of choices is 42 if a local department store sells carpets in 4 sizes. Each carpet comes in 3 different qualities. One of the sizes comes in 5 colors.

What are permutation and combination?

A permutation is the number of different ways a set can be organized; order matters in permutations, but not in combinations.

It is given that:

A local department store sells carpets in 4 sizes.

Each carpet comes in 3 different qualities.

One of the sizes comes in 5 colors.

The other sizes come in 3 colors.

The number of choices can be found as follows:

= 1x3x5

= 15

= 3x3x3

= 27

Total number of choices = 15 +27

= 42

Thus, the total number of choices is 42 if a local department store sells carpets in 4 sizes. Each carpet comes in 3 different qualities. One of the sizes comes in 5 colors.

Learn more about permutation and combination here:

brainly.com/question/2295036

#SPJ2

there are 60 choices of carpet

reason:
4*3*5
12*5
=60
or
4*3*5
4*15
=60

hector works 12 hours a week at a part time job. His original pay rate was $8 per hour but he recently received a pay raise of x dollars an hour. his new total weekly pay, y, is represented by the equaiton y=12(8+x)

Answers

Missing:

If Hector earned $126 last week, what was the amount of Hector's raise per hour?

Answer:

$x = 2.5$

Step-by-step explanation:

Given

$y=12(8+x)$

Required

Solve for x when y = 126

$y=12(8+x)$

$126 = 12(8 + x)$

Divide through by 12

$(126)/(12) = (12(8 + x))/(12)$

$10.5 = 8 + x$

$x = 10.5 - 8$

$x = 2.5$

What is the solution to the system of equations y = -4/5x + 6 and y = -30A) (45,-30)
B) (-30,30)
C) (-30,45)
D) (30,-30)

Answers

Hi There!

Answer: A) (45,-30)

Why: x = 45 and y = -30

-30 = -4/5(45) + 6

-30 = -36 + 6

-30 = -30

Hope This Helps :)

Answer:

A is the correct answer

Step-by-step explanation:

took the exam

a radio station claims that the amount of advertising per hour of broadcast time has an average of 17 minutes and a standard deviation equal to 2.7 minutes. You listen to the radio station for 1 hour, at a randomly selected time, and carefully observe that the amount of advertising time is equal to 11 minutes. Calculate the z-score for this amount of advertising time

Answers

Answer:

z-score for 11 minutes of advertising time is $z=(-6)/(2.7)\approx -2.222$

Step-by-step explanation:

Z-scores measure the distance of any data point from the mean in units of standard deviations and are useful because they allow us to compare the relative positions of data values in different samples.

The z-score for any single data value can be found by the formula:

$z=(data \:value- \:mean)/(standard \:deviation)$

From the information given we know:

Data value = 11 minutes
Mean = 17 minutes
Standard deviation = 2.7 minutes

$z=(11-17)/(2.7) = (-6)/(2.7)\approx -2.222$

A social scientist believed that less than 30 percent of adults in the United States watch 15 or fewer hours of television per week. To test the belief, the scientist randomly selected 1,250 adults in the United States. The sample proportion of adults who watch 15 or fewer hours of television per week was 0.28, and the resulting hypothesis test had a p-value of 0.061. The computation of the p- value assumes which of the following is true? (A) The population proportion of adults who watch 15 or fewer hours of television per week is 0.28. Submit

(B) The population proportion of adults who watch 15 or fewer hours of television per week is 0.30.

(C) The population proportion of adults who watch 15 or fewer hours of television per week is less than 0.30.

(D) The population mean number of hours adults spend watching television per week is 15.

(E) The population mean number of hours adults spend watching television per week is less than 15.

Answers

The population proportion of adults who watch 15 or fewer hours of television per week is less than 0.30.

Given that,

A social scientist believed that less than 30 percent of adults in the United States watch 15 or fewer hours of television per week.

The scientist randomly selected 1,250 adults in the United States. The sample proportion of adults who watch 15 or fewer hours of television per week was 0.28,

And the resulting hypothesis test had a p-value of 0.061.

We have to determine,

The computation of the p- value assumes which of the following is true.

According to the question,

Let, The proportion of adults watching televisionless than or equal to 15% be = x

Null Hypothesis [H0] : x = 30% = 0.30

Alternate Hypothesis [H1] : x < 30% , or x < 0.30

P value is calculated at z value :

$= P_1- \sqrt(p_o(1-p_o))/(n)}$

Where p' = 0.28, $P_0$ = 0.30, $P_1$ = 0.70 ;

Then,

$= 0.70- \sqrt(0.30(1-0.30))/(1250)}\n\n= 0.70- \sqrt{(0.30 * 0.70 )/(1250) }\n\n= 0.70 - 0.012\n\n= 0.61$

Assuming 10% level of significance, p = 0.10

Therefore, p value 0.061 < 0.10, reject H0 & accept H1. This implies that we conclude that 'x i.e. proportion of adults watching television less than or equal to 15% < 30% or 0.30'

Hence, The population proportion of adults who watch 15 or fewer hours of television per week is less than 0.30.

To know more about Sample proportion click the link given below.

brainly.com/question/13846904

Answer:

Step-by-step explanation:

Let the proportion of adults watching television less than or equal to 15% be = x

Null Hypothesis [H0] : x = 30% = 0.30
Alternate Hypothesis [H1] : x < 30% , or x < 0.30

P value is calculated at z value : p' - [ √ { p0 (1- p0) } / n ] ;

where p' = 0.28, p0 = 0.30, p1 = 0.70 ; ∴ p ( z < -1.543) = 0.061

Assuming 10% level of significance, p = 0.10

As p value 0.061 < 0.10, we reject H0 & accept H1. This implies that we conclude that 'x ie proportion of adults watching television less than or equal to 15% < 30% or 0.30'

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