Please help I need help with this question??)):
please help I need help with this question??)): - 1

Answers

Answer 1
Answer:

Answer:

fourth degree monomial

Step-by-step explanation:

This is the answer by definition.


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Please show work with answer

Answers

14.

∠A ≅ ∠T . . . . given

AX ≅ TX . . . . given

∠AXM ≅ ∠TXH . . . . vertical angles are congruent

ΔAXM ≅ ΔTXH . . . . ASA theorem

MX ≅ HX . . . . CPCTC

___

15.

The acronyms that invoke theorems based on two or three sides being congruent are inapplicable in this case.

SSS

SAS

Combine like terms to create an equivalent expression. 1/7 - 3 (3/7n - 2/7)

Answers

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▹ Answer

1 - 9/7n

▹ Step-by-Step Explanation

1/7 - 3(3/7n - 2/7)

Remove the parentheses (Distribute -3 among the parentheses):

1/7 - 9/7n + 6/7

Calculate:

1 - 9/7n

Hope this helps!

CloutAnswers ❁

━━━━━━━☆☆━━━━━━━

Answer:

1-9/7n

Step-by-step explanation:

(1)/(7)-3((3)/(7)n-(2)/(7)  ) \n=(1)/(7)-(9)/(7)n  +(6)/(7) \n=(1-9n+6)/(7) \n=(7-9n)/(7)\n=1-(9)/(7)n

Is this right? please correct me if I'm wrong.

Answers

Answer:

Yes it seems that it is right

A second number is 7 less than the first number. The third number is twice the first number. If the sum of the three numbers is 321, find the numbers

Answers

Answer:

x=4

Step-by-step explanation:

hope it will help

First no.=x

2nd no.=2x

3rd no. =2x+6

x+2x+2x+6=26

5x+6=26

5×=26-6

5x =20.......divide both sides by 5

x=4

1st no.=x=4

the points j(-8,9) and k(-2,-5) are endpoints of a diameter of circle C. What equation would represent circle C

Answers

The equation of circle C will be;

⇒ (x + 5)² + (y - 2)² = 7.61²

What is Circle?

The circle is a closed two dimensional figure , in which the set of all points is equidistance from the center.

Given that;

The points j(-8,9) and k(-2,-5) are endpoints of a diameter of circle C.

Now,

Since, The points j(-8,9) and k(-2,-5) are endpoints of a diameter of circle C.

Hence, The diameter of circle = √(- 2 - (-8))² + (- 5 - 9)²

                                               = √ 6² + 14²

                                               = √36 + 196

                                               = √232

                                               = 15.23

Thus, The radius of circle = 15.23 / 2

                                        = 7.61

And, The center of the circle = (- 8 + (-2)) / 2 , (9 + (-5))/2

                                             = (- 5, 2)

So, The equation circle C is,

⇒ (x - (-5))² + (y - 2)² = 7.61²

⇒ (x + 5)² + (y - 2)² = 7.61²

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Answer:

(x+5)² + (y-2)² =58

Step-by-step explanation:

"Your answer needs to be at least 20 characters long"

Let S(x, y) denote the statement "x has seen y" and D denote the set of all students in our class and M be the set of all movies.a. Express the following English sentence as a quantified proposition using the definitions above:
"For every movie there is a pair of students in our class who have both seen it." Hint: Use three quantifiers - one for the movie and two for a pair of students.

b. Negate the quantified proposition you wrote for part (a) (i.e., place a "¬" in front of it). Use de Morganâs law for quantifiers to move the negation inside the quantifiers.
c. Translate you answer for part (b) back to plain English.

Answers

Answer:

Step-by-step explanation:

a) Recall the quantifiers \forall, \exists.

Then, we can translate the proposition as follows

\forall m \in M \exists x \in D \exists y \in D S(x,m)\land S(y,m)

b) Recall that an expression of the form \exists x P(x) its negation is of the form \forall x \neg P(x) which means that it is not true that for all elements the proposition P holds. Equivalently, we have that the negation of an expression of the form \forall x P(x) is \exists x \neg P(x) which means that there is at least one x such that P doesn't hold. Using this, we get the following

\neg(\forall m \in M \exists x \in D \exists y \in D S(x,m)\land S(y,m))= \exists m \in M \neg (\exists x \in D \exists y \in D S(x,m)\land S(y,m))= \exists m \in M \forall x \in D \neg (\exists y \in D S(x,m)\land S(y,m))= \exists m \in M \forall x \in D \forall y \in D \neg(S(x,m)\land S(y,m))

By De Morgan's law, we have that \neg (A \land B) = \neg A \lor \neg B

So, the final statement is

\exists m \in M \forall x \in D \forall y \in D \neg S(x,m) \lor \neg S(y,m)

c)

This statement means: There is a movie that for every pair of students, at least one of the students hasn't seen the movie yet.

Final answer:

The quantified proposition expresses that for every movie, there is a pair of students who have both seen it. The negated proposition states that there exists a movie that no pair of students have both seen.

Explanation:

a. The English sentence can be expressed as the quantified proposition: ∀m ∈ M, ∃ (s1, s2) ∈ D^2, S(s1,m) ∧ S(s2,m)
b. The negation of the quantified proposition is: ∃m ∈ M, ∀(s1, s2) ∈ D^2, ¬(S(s1,m) ∧ S(s2,m))
c. The translation of the negated proposition is: There exists a movie that no pair of students in our class have both seen.

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