Answer:
Step-by-step explanation:
as mentioned in question that sum of 3 consecutive integer is 117
let the first integer be x equation(1)
second integer as x+1 equation(2)
third integer as x+2 equation (3)
so the sum of these three equation will be equal to 117
x+x+1+x+2=117
3x+3=117
3x=114
x=38
so first integer is 38
from equation 2 the value of second integer will be 39
from equation 3 he value of third integer will be 40
so he correct answer is a) 38,39,40
42
11
I'm pretty sure its 45
B.commutative
C.distributive
D.reflexive
Which answer is right !
Leila used the distributive property in the first step to solve the given equation, multiplying both terms in the parentheses by the fraction 2/3.
In this step, Leila applied the distributive property. The distributive property states that a(b + c) = ab + ac. This property allows us to multiply a single term by two or more terms within a parenthesis. In this case, Leila multiplied the fraction 2/3 by both 'x' (the variable) and '5' (the constant), inside the parentheses.
So, the equation went from 2/3 (x + 5) to (2/3 * x) + (2/3 * 5), which follows the rule of distributive property ab + ac when applied to the given equation.
#SPJ3
Answer:
Step-by-step explanation:
pi - 1 = 3.14 - 1 = 2.14
x has to be an integer, and the result must be greater than 1.
1 works.
1 < 2.14*1 < 10 2.14 is between 1 and 10.
2 works
1 < (2.14)*2 < 10
1 < 4.28 < 10
3 works
1 < 2.14 * 3 < 10
1 < 6.42 < 10
4 might work
1 < 2.14*4 < 10
1 < 8.56 < 10
and it does work.
5 can't work
1 < 5 * 2.14 < 10
1 < 10.7 < 10 is not true.
Answer: 1,2,3,4
Answer:
10
Step-by-step explanation:
pi is 3.14...
pi - 1 is 2.14...
question becomes 1<2.14x and 2.14x < 10
1/2.14 < x, 0.46... < x
x < 10/2.14, x < 4.67...
combining
0.46< x < 4.67
x can be 1, 2, 3, 4
Base = 12cm