How tall is the table?
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Related Questions
Given:AB||CD .If the coordinates of point A are (8, 0) and the coordinates of point B are (3, 7), the y-intercept of AB is____ ? If the coordinates of point D are (5, 5), the equation of line CD is y___ = ___x + ____
You are planning to take to a trip to Montreal, Canada during the month of April and you want to bring clothing that is appropriate for the weather. The daily high temperature X in degrees Celsius in Montreal during April has expected value E(X) = 10.3oC with a standard deviation SD(X) = 3.5oC. You want to convert these Celsius temperatures to oF (degrees Fahrenheit). The conversion of X into degrees Fahrenheit Y is Y = (9/5)X + 32.1. What is E(Y), the expected daily high in Montreal during April in degrees Fahrenheit?2. What is SD(Y), the standard deviation of the daily high temperature in Montreal during April in degrees Fahrenheit?
Can anyone help me please?
15 yards to 18 yards
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20+20=40÷4=44
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Answer:
The length and width that maximize the area are:
W = 2*√8
L = 2*√8
Step-by-step explanation:
We want to find the largest area of a rectangle inscribed in a semicircle of radius 4.
Remember that the area of a rectangle of length L and width W, is:
A = L*W
You can see the image below to see how i will define the length and the width:
L = 2*x'
W = 2*y'
Where we have the relation:
4 = √(x'^2 + y'^2)
16 = x'^2 + y'^2
Now we can isolate one of the variables, for example, x'
16 - y'^2 = x^'2
√(16 - y'^2) = x'
Then we can write:
W = 2*y'
L = 2*√(16 - y'^2)
Then the area equation is:
A = 2*y'*2*√(16 - y'^2)
A = 4*y'*√(16 - y'^2)
If A > 1, like in our case, maximizing A is the same as maximizing A^2
Then if que square both sides:
A^2 = (4*y'*√(16 - y'^2))^2
= 16*(y'^2)*(16 - y'^2)
= 16*(y'^2)*16 - 16*y'^4
= 256*(y'^2) - 16*y'^4
Now we can define:
u = y'^2
then the equation that we want to maximize is:
f(u) = 256*u - 16*u^2
to find the maximum, we need to evaluate in the zero of the derivative:
f'(u) = 256 - 2*16*u = 0
u = -256/(-2*16) = 8
Then we have:
u = y'^2 = 8
solving for y'
y' = √8
And we know that:
x' = √(16 - y'^2) = √(16 - (√8)^2) = √8
And the dimensions was:
W = 2*y' = 2*√8
L = 2*y' = 2*√8
These are the dimensions that maximize the area.
Always
Never
Sometimes
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Answer:
AB in terms of rays, can never be BA.
Step-by-step explanation:
AB and BA name the same ray.
No, this is never true. A ray starts from a point and move in a single direction to infinity.
So, if starting point is A and ray is moving towards B, so it will continue moving towards the points further from B.
Therefore, AB as in terms of rays, can never be BA.
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Subtraction Property of Equality
Multiplication Property of Equality
Division Property of Equality
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p/7 - 5 = -3
Add 5 to each side. (Addition property.)
p/7 = 2
Multiply each side by 7. (Multiplication property.)
p = 14
1 over 28. miles per gallon
28 miles per gallon
448 miles per 16 gallons
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Answer:
Step-by-step explanation:
28 miles per gallon
Final answer:
Blake drives 28 miles on one gallon of gas. To find this, we divided the total miles driven, which was 448, by the number of gallons used, which was 16.
Explanation:
To find out how many miles Blake drives per gallon, we need to divide the total miles driven by the total gallons used. In this case, Blake has driven 448 miles using 16 gallons of gas. So, we perform the calculation:
448 miles ÷ 16 gallons = 28 miles per gallon
Therefore, Blake drives 28 miles for every gallon of gas.
Learn more about Dividing Numbers here:
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