Do you have to regroup to find 523 - 141?

Answers

Answer 1

Answer: yeah you have to regroup and if this app doesn't help you can go to a library that has homework help p.s. this is a tip

Answer 2

Answer: Yes you need to regroup because of 2 and 4 :)

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PLEASE HELP with these math questions (Please don't answer if you don't know all of them)

Answers

sqrt (53) = 10 * sqrt (0.53)

0.53 = 64/121
sqrt (0.53) = sqrt (64)/ sqrt (121) = 8/11 = 0.7273
Therefore sqrt (53) = 10 * 0.7273 = 7.27

sqrt (108) = 10 * sqrt (1.08)
sqrt (1.08) = sqrt (676/625) = 26/25 = 1.04
Therefore sqrt (108) = 10 * 1.04 = 10.4

sqrt (128) = 10 * sqrt (1.28)
sqrt (1.28) = sqrt (289/225) = 17/15 = 1.133
Therefore sqrt (108) = 10 * 1.133 = 11.33

Can someone help me out!!!??? Please

Answers

Answer:

see below

Step-by-step explanation:

The two marked points are equidistant from their average, which is ...

(-3 +9)/2 = 6/2 = 3

The distance they are from that average is 9-3 = 3 -(-3) = 6.

So, you want an expression that is equivalent to ...

|x -3| = 6

Subtracting 1 from both sides of this equation gives you the one seen in choice B:

|x -3| -1 = 5

Given that (4p-5q)/(6p+q) = 1/4 , find the value of 2p : 7q in its lowest term.

Answers

Start from

$\cfrac{4p-5q}{6p+q} = \cfrac{1}{4}$

and cross multiply the denominators (i.e. multiply both sides by $4(6p+q)$

The result is

$4(4p-5q) = 6p+q$

Expand the left hand side:

$16p-20q = 6p+q$

Bring all terms involving p to the left, and all terms involving q to the right:

$16p-6p = 20q+q \implies 10p=21q$

Divide both sides by 21q:

$\cfrac{10p}{21q} = 1$

Now we have a ratio between multiples of p and q. It's not exactly the one we want, though. Nevertheless, we can keep multiplying both sides by approriate constants in order to get the ratio we want:

Divide both sides by 5:

$\cfrac{2p}{21q} = \cfrac{1}{5}$

Multiply both sides by 3:

$\cfrac{2p}{7q} = \cfrac{3}{5}$

Can u please answer my question

Answers

1st Step:We should first change them all to have a common denominator.
2nd Step:We should find the least common multiple
4×1=4 8×1=8 16×1=16
4×2=8 8×2=16
4×3=12
4×4=16
LCM is 16

$(1*4)/(4*4)$ + $(1*2)/(8*2)$ + $(1)/(16)$
$(4)/(16)$ + $(2)/(16)$ + $(1)/(16)$
$(7)/(16)$

$(7)/(16)$ is the fraction of the page that is used in total.

turn the denominators into the same number by multipling them
same to top as to bottom so
1/4 =4/16
1/8= 2/16
1/16 stays the same

add together to get 7/16

Numbers to the power of a fraction help pls