Help me, please !! For a reason, Tony took 1/3 his money for book and then he took 1/5 again for beer. And now tony have 28$, how many money he had before? Please anwer with the pattern, thank you

Answers

Answer 1

Answer: (1-1/3)x*(1-1/5)=28 8/15x=28 x=52.5. Therefore, he had 52.5$before

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Dejah is proving that perpendicular lines have slopes that are opposite reciprocals. She draws line s and labels two points on the line as (−a, 0) and (0, b).Enter the answers, in simplest form, in the boxes to complete the proof.

Answers

Answer:

math is hard :(

Step-by-step explanation:

Use the given degree of confidence and sample data to construct a confidence interval for the population mean mu μ. Assume that the population has a normal distribution. A laboratory tested twelve chicken eggs and found that the mean amount of cholesterol was 185 milligrams with s equals =17.6 milligrams. Construct a 95% confidence interval for the true mean cholesterol content of all such eggs A. 175.9 mg less than < mu μ less than <194.1 mg
B. 173.9 mg less than < mu μ less than <196.1 mg
C. 173.8 mg less than < mu μ less than <196.2 mg
D. 173.7 mg less than < mu μ less than <196.3 mg

Answers

Answer:

option (C) 173.8 mg less than < mu μ less than <196.2 mg

Step-by-step explanation:

Data provided ;

number of sample, n = 12

Mean = 185 milligram

standard deviation, s = 17.6 milligrams

confidence level = 95%

α = 0.05 [for 95% confidence level]

df = n - 1 = 12 - 1 = 11

Now,

Confidence interval = Mean ± E

here,

E is the margin of error = $t_(\alpha/2, df)(s)/(√(n))$

also,

$t_(\alpha/2, df)$

= $t_(0.05/2, (11))$

= 2.201 [ from standard t value table]

Thus,

E = $2.201*(17.6)/(√(12))$

E = 11.182 milligrams ≈ 11.2 milligrams

Therefore,

Confidence interval:

Mean - E < μ < Mean + E

185 - 11.2 < μ < 185 + 11.2

173.8 < μ < 196.2

Hence,

the correct answer is option (C) 173.8 mg less than < mu μ less than <196.2 mg

Final answer:

To construct a confidenceinterval for the population mean cholesterol content of all chicken eggs with a 95% confidence level, we use the sample mean, standard deviation, and sample size to calculate the margin of error. The confidence interval is then constructed by subtracting the margin of error from the sample mean and adding it to the sample mean.

Explanation:

To construct a confidenceinterval for the population mean cholesterol content of all chicken eggs, we first need to find the margin of error. The margin of error depends on the samplemean, standard deviation, sample size, and the desired level of confidence. In this case, we have a sample mean of 185 mg, a standard deviation of 17.6 mg, and a sample size of 12. Since we want a 95% confidence interval, we use a z-score of 1.96. The margin of error is then calculated as 1.96 * (17.6/sqrt(12)), which is approximately 9.61 mg. We can then construct the confidenceinterval by subtracting the margin of error from the sample mean and adding it to the sample mean. Therefore, the 95% confidence interval for the true mean cholesterol content of all such eggs is 175.9 mg to 194.1 mg.

Learn more about Constructing confidence intervals here:

brainly.com/question/32824150

#SPJ12

The third and the sixth term of a geometric progression are 24 and 64/9 respectively. Finda) the first term and common ratio
b) the sum of the first five terms

Answers

Answer:

Ai. Common ratio = 2/3

Aii. First term = 54

B. Sum of the first five terms = 422/3

Step-by-step explanation:

From the question given above, the following data were obtained:

3rd term (T3) = 24

6Th term (T6) = 64/9

First term (a) =?

Common ratio (r) =?

Sum of the first five terms (S5) =?

Ai. Determination of the common ratio (r).

T3 = ar²

T3 = 24

24 = ar²....... (1)

T6 = ar⁵

T6 = 64/9

64/9 = ar⁵......... (2)

The equation are:

24 = ar²....... (1)

64/9 = ar⁵......... (2)

Divide equation 2 by equation 1.

64/9 ÷ 24 = ar⁵ / ar²

64/9 × 1/24 = r³

8/27 = r³

Take the cube root of both side

r = 3√(8/27)

r = 2/3

Thus, the common ratio is 2/3

Aii. Determination of the first term (a).

T3 = ar²

3rd term (T3) = 24

Common ratio (r) = 2/3

First term (a) =?

24 = a(2/3)²

24 = 4a/9

Cross multiply

24 × 9 = 4a

216 = 4a

Divide both side by 4

a = 216/4

a = 54

Thus, the first term (a) is 54

B. Determination of the sum of the first five terms.

Common ratio (r) = 2/3

First term (a) = 54

Number of term (n) = 5

Sum of first five terms (S5) =?

Sn = a[1 –rⁿ] / 1 – r

S5 = 54[1 – (⅔)⁵] / 1 – ⅔

S5 = 54 [1 – 32/243] / ⅓

S5 = 54 (211/243) × 3

S5 = 54 × 211/81

S5 = 6 × 211/9

S5 = 2 × 211/3

S5 = 422/3

Thus, the sum of the first five terms is 422/3

-189=4x-3(-4+15) WHAT IS THE ANSWER TO THIS PROBLEM?

Answers

Answer:

4/15

Step-by-step explanation:

Answer: x= -39

Step-by-step explanation: Let's solve your equation step-by-step.

−

189

−

(

−

)

Step 1: Simplify both sides of the equation.

−

189

−

(

−

)

−

189

−

189

−

Step 2: Flip the equation.

−

189

Step 3: Add 33 to both sides.

−

189

−

156

Step 4: Divide both sides by 4.

−

156

−

a.Find a linear approximation of 4√14 . b. Justify visually whether your approximation is an over- or underestimate.

Answers

Answer:

Step-by-step explanation:

Let f(x) be the function

$\bf f(x)=√(x)$

A linear approximation of f is the Taylor polynomial of degree one:

$\bf f(x)\approx f(a)+f'(a)(x-a)$

Taking a = 16, and given that

$\bf f'(x)=\displaystyle(1)/(2√(x))$

we get

$\bf f(x)\approx f(16)+f'(16)(x-16)=√(16)+\displaystyle(1)/(2√(16))(x-16)=4+\displaystyle(x-16)/(8)$

$\bf √(14)=f(14)\approx 4+\displaystyle(14-16)/(8)=3.75\Rightarrow\n\n\Rightarrow 4√(14)\approx 4(3.75)=15$

Since 16 > 14, we can deduce that this is an overestimate.

What is the slope intercept equation of the line below. Y-intercept=(0,2) slope=3/4

Answers

Answer:

y = 3/4x +2

Step-by-step explanation:

The slope intercept form of an equation is

y = mx+b

where m is the slope and b is the y intercept

Y-intercept=(0,2) slope=3/4

y = 3/4x +2

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What is 421906 rounded to the nearest hundred thousand