Same Question here answered by me correctly . Visit the link below for your answer
x+2y=10 2x-3y=-9
Solution of the system:
or as ordered pair: (2, 4)
Remember that the point of intersection of two lines is the solution of the system of linear equations. We know from our graph that our lines intersect at the point (1.7, 4.1), so the solution of our system of linear equations is (1.7, 4.1).
Now, to obtain the nearest integer of a decimal, we focus on the number after the decimal point: if the number is five or bigger than five, we add 1 to our integer; if the number is less than five, we keep the integer as it is.
For 1.7
The number after the decimal point is 7. Since 7 is bigger than 5, we add 1 to our integer, so the nearest integer of 1.7 is 2
For 4.1
The number after the decimal point is 1. Since 1 is less than 5, we keep our integer as it is, so the nearest integer of 4.1 is 4
The area of the sector with a central angle of 210° and a diameter of 4.6units is 2.6π square units.
Area is a collection of two - dimensional points enclosed by a single dimensional line. Mathematically, we can write -
V = ∫∫F(x, y) dx dy
Given is a sector with a central angle of 210° and a diameter of 4.6 units.
The area of a sector can be calculated using the formula -
A{Sector} = θ/360° x 2πr
For the sector given, we have -
θ = 210°
r = 4.6 units
Substituting the values, we get the area of the sector as -
A{Sector} = 210°/360° x 2πr
A{Sector} = 7/12 x 2πr
A{Sector} = 7πr/6
A{Sector} = 7πd/12
A{Sector} = 7π x 4.6/12
A{Sector} = 7π x 0.38
A{Sector} = 2.6π square units
Therefore, the area of the sector with a central angle of 210° and a diameter of 4.6units is 2.6π square units.
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Answer:
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Step-by-step explanation:
where are the options?
Answer:
ABQ = 139
BCR is the same as QBC since they are alternate interior angles
BCR = 41
Step-by-step explanation:
CBQ and SCB are same side interior angles so they add to 180
2a-9 + 5a +14 = 180
Combine like terms
7a +5 = 180
Subtract 5 from each side
7a = 175
Divide by 7
7a/7 = 175/7
a = 25
ABQ is the same as SCB since they are corresponding angles so
ABQ = SCB = 5a+14 = 5*25+14 = 125+14 = 139
BCR is the same as QBC since they are alternate interior angles
BCR = QBC = 2a-9 = 2*25 -9 = 50-9 = 41