Answer:
40%
Step-by-step explanation:
11+24+16+9=60
24/60=2/5
.40
40%
Answer:
The equation of the line, using the point-slope form, through (-4,6) that is parallel to the line will be:
Step-by-step explanation:
We know that the slope-intercept form is
Where m is the slope and b is the y-intercept
Given the equation
comparing with the slope-intercept form
slope = m = -5
y-intercept = b = 2
We know that the parallel lines have the same slopes.
so, the slope of the parallel line will be: -5
Thus, the equation of the line, using the point-slope form, through (-4,6) that is parallel to the line will be:
Answer:
y=-x+2
Step-by-step explanation:
i already did it and your welcome in advance
Answer:
51
Step-by-step explanation:
5 ×(10 :10 ×10) +(8 ×3 - 23) =
5 ×(1 ×10) +(24 - 23) =
5 ×10 +1 =
50 +1 =
51
2y+2=3y/2
Please help me
Answer:-4
Step-by-step explanation:
2y+2=3y/2
Cross multiply
2(2y+2)=3y
Open bracket
4y+4=3y
Collect like terms
4y-3y=-4
y=-4
Answer:
2.131
Step-by-step explanation:
Given : Sample size = 16
Sample mean is 4.2
Sample standard deviation is 1.4.
Level of significance is 0.05.
To Find : critical t value
Solution:
Sample size = 16
Since n < 30
So we will use t - test
We are supposed to find critical t value
Degree of freedom = n-1 = 16-1 = 15
Level of significance =α= 0.05
Now refer the t table for t critical
= = 2.131
Hence The critical t value for this problem is 2.131
The value of x + y from the equation is 15
The equation is given as:
Add 125 to both sides of the equation
Express 125 as 100 + 25
Rewrite the equation as:
Group the expressions
Express the expressions in both groups as perfect squares
Possible equations from the above equation is:
and
Take the square roots of both sides
and
Solve for x and y in the above equations
and
So, we have:
Hence, the value of x + y is 15
Read more about quadratic functions at:
Answer:
it is true
Step-by-step explanation:
A test statistic compares our observed outcome to the alternative hypothesis. If the null hypothesis is true, then the teststatistic will be close to 0. Therefore, the farther the test statistic is from 0, the more the null hypothesis is discredited.