Answer:
2x
Step-by-step explanation:
Because both terms are divisible by 2x. So, that's the greatest common factor. Whichever term is the greatest and can divide both the numbers it the GFC.
Answer:
D
Step-by-step explanation:
When an equation shifts down, you simply subtract the amount of units and when it shifts up, you add the amount of units so since it is 2 units down, it is -2
Answer:
D
Step-by-step explanation:
It is D because 'moving it down 2 spaces' has to do with the y-axis. If you move a line 2 spaces down then you are moving it down by -2.
Answer:
The answer is 17.02, to the nearest tenth is 17.
Step-by-step explanation:
Under the radical, that us take the square root of the following sum:
(Jx - Cx )^2 + (Jy - Cy)^2
Substitute in the values:
(6 - (-7))^2 + (2 - (-9))^2 =
This becomes:
(6+7)^2 + (2 + 9)^2 =
13^2 + 11^2 =
169 + 121 =
Sqrt 290 =
17.029 = To the nearest 10th is 17
Diagram A:
Which
addition
models
subtrac
100% of x
1096 10% 10% 10% 10% 1096 1096 1096 1096 1096
80% of x
20% of x
Diagram B:
120% of
10% 10% 1096 1096 10% 10% 10% 10% 10% 1096 10% 10%
100% of x
2096 of x
a.
Your bill at a restaurant is $68 and you want to leave
a 20% tip. What is the total amount you will leave?
b. You buy a sweater that is on sale for 20% off of the
original price. The sweater cost $28. What was the
original price?
Answer:
a
Step-by-step explanation:
Answer:
Power analysis
Step-by-step explanation:
Power analysis is a significant part of test structure. It permits us to decide the example size required to recognize an impact of a given size with a given level of certainty. On the other hand, it permits us to decide the likelihood of recognizing an impact of a given size with a given degree of certainty, under example size requirements. On the off chance that the likelihood is unsuitably low, we would be shrewd to adjust or forsake the analysis.
The principle reason underlying power analysis is to assist the analyst with determining the littlest example size that is appropriate to recognize the impact of a given test at the ideal degree of hugeness.
Answer:
V= 22-2t
Step-by-step explanation:
I guess the alphabet should be v instead of y. So I am working using v
The rate at which water is draining from the tank is 2gallons/hour. This is the rate of water removal from the tank. So after an hour, 2 × 1= 2 gallons would have drained. After 5 hours, 2×5 =10 gallons would have drained
Therefore to obtain the amount of water in gallons that have been removed from the tank, you will multiply the rate by the time in hours after which the draining started.
Amount (gallons) =2×t
The amount of water remaining in the tank will be obtained by subtracting the amount of water drained after some hour (2×t) from the initial amount of water in the tank (22)
Therefore, the amount of water present in the tank (v)= 22-2t or 2(11-t) gallons
The formula to express volume of the water v in terms of time t is v = 22 - 2t, where 22 is the initial volume and 2t represents the rate at which the water is draining.
This problem is a mathematical representation of a real-world scenario using a linear equation. The volume of water v in the tank can be represented in terms of time t through the equation v = 22 - 2t. This equation illustrates the initial volume of water in the tank (22 gallons) and accounts for the constant rate at which the water is draining (2 gallons per hour).
When time t = 0 (meaning no time has passed since the water started draining), the volume of water v = 22 (the initial volume). As time increases, the volume gradually decreases at a rate of 2 gallons per hour, represented by the term -2t.
#SPJ3
9.0, 7.3, 6.0, 8.8, 6.8, 8.4, and 6.6 pounds.
If Alpha = 0.05,
1. What is the critical t-value?
2. What is the decision for a statistically significant change in average weights at birth at the 5% level of significance?
Answer:
1. Critical value t=±2.447
2. The null hypothesis is failed to be rejected.
At a significance level of 0.05, there is not enough evidence to support the claim that the birth weight significantly differs from 6.6 lbs.
Step-by-step explanation:
This is a hypothesis test for the population mean.
The claim is that the birth weight significantly differs from 6.6 lbs.
Then, the null and alternative hypothesis are:
The significance level is 0.05.
The sample has a size n=7.
The sample mean is M=7.56.
As the standard deviation of the population is not known, we estimate it with the sample standard deviation, that has a value of s=1.18.
The estimated standard error of the mean is computed using the formula:
Then, we can calculate the t-statistic as:
The degrees of freedom for this sample size are:
For a two-tailed test with 5% level of significance and 6 degrees of freedom, the critical value for t is ±2.447.
As the test statistic t=2.152 is under 2.447 and over -2.447, it falls in the acceptance region, so the effect is not significant. The null hypothesis is failed to be rejected.
At a significance level of 0.05, there is not enough evidence to support the claim that the birth weight significantly differs from 6.6 lbs.
Sample mean and standard deviation calculations: