What is the point on the unit circle for the angle below?

Answers

Answer 1

Answer:

Answer:

xcvbnm

Step-by-step explanation:

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How many 3/4 inch strips for caulk to cover 10 1/2 inches
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Mr. Hoya brought 5 watermelons from his grocery store. The watermelons weighed 8.25 pounds, 9.25 pounds, 8.875 pounds, 9.625 pounds and 10.75 pounds. At the party, 153 people each ate a 0.25 pound serving of watermelon. Was the amount of leftover watermelon less than, greater than, or equal to 8.5 pounds? Explain how to solve the problem.

Answers

The first thing we must do for this case is to find the total weight of the watermelons.
We have then:
$W = 8.25 + 9.25 + 8.875 + 9.625 + 10.75 W = 46.75 pounds$
We now look for the amount of watermelons that people ate.
We have then:
$(0.25) * (153) = 38.25 pounds$
Therefore, the amount of watermelon remaining is:
$46.75 - 38.25 = 8.5 pounds$
We note that the amount of watermelon remaining is equal to 8.5 pounds.
Answer:
the amount of leftover watermelon is: equal to 8.5 pounds

Answer:
The amount of leftover watermelon is equal to 8.5 pounds

Explanation:
1- getting the total weight of the watermelon:
The total weight of the watermelon will be the summation of the weights of the 5 watermelons he bought.
This means that:
Total weight = 8.25 + 9.25 + 8.875 + 9.625 + 10.75
Total weight = 46.75 pounds

2- getting the weight of the eaten watermelon:
We know that at the party, there were 153 people and each ate 0.25 of a pound of watermelon.
This means that:
amount eaten = 153 * 0.25
amount eaten = 38.25 pounds

3- getting the weight of the leftover:
weight of leftover = total weight - amount eaten
We have:
Total weight = 46.75 pounds
amount eaten = 38.25 pounds
Therefore:
weight of leftover = 46.75 - 38.25
weight of leftover = 8.5 pounds

Hope this helps :)

Identify the equation that correctly shows the given relationship.

Answers

It’s A he is correct and have a good day

The length of a rectangle is 5ft longer than twice the width if the perimeter is 58 ft find the length and width of the rectangle

Answers

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Define x :
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Let the width be x.
Width = x
Length = 2x + 5 // Length is 5ft longer than twice the width

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Formula for Perimeter :
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Perimeter = 2 (Length + Width)

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Find Width :
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58 = 2 ( 2x + 5 + x) // Substitute Length and Width into formula
58 = 2 (3x + 5) // Combine like terms
58 = 6x + 10 // Apply distributive property
48 = 6x // Take away 10 from both sides
6x = 48 // Switch sides. Make x the subject
x = 8 // Divide by 6 on both sides

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Find Length and Width :
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Width = x = 8 ft
Length = 2x + 5 = 2(8) + 5 = 21 ft

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Answer: The length is 21 ft and the width is 8 ft.
--------------------------------------------------------------------

Length= 5+2x
Width = x

Perimeter = 2(l+w)=58
= 2(5+2x+x)=58
= 2(5+3x)=58
= 10+6x =58
= 6x= 48
X= 8
Width=8
Length= 21

Nando has 2 goldfish. Jill has 5 goldfish Cooper has 2 times as many goldfish as Nando and Jill combined

Answers

Answer:

cooper has 14 goldfish

Step-by-step explanation:

because cooper has 2 times as many as Nando (2) and Jill (5) combined so 7 ( 5+2) times 2 is 14. 14 goldfish

Answer:

Step-by-step explanation:

A solid is formed by adjoining two hemispheres to the ends of a right circular cylinder. An industrial tank of this shape must have a volume of 4640 cubic feet. The hemispherical ends cost twice as much per square foot of surface area as the sides. Find the dimensions that will minimize the cost. (Round your answers to three decimal places.)

Answers

The dimensions that minimize the cost of building the tank are $r\approx 6.5ft \text{ and } h \approx 26.0ft$ .

Let

$h=\text{the height of the cylindrical sides}\nr=\text{the radius of the hemispheres and the cylindrical sides}$

and

$T=\text{the total cost}\nu_c=\text{the unit cost of building the cylindrical sides}\nu_h=\text{the unit cost of building the hemispherical surfaces}$

and

$S_c=\text{the surface area of the cylinder}\n=2\pi rh\n\nS_h=\text{the total surface area of both hemispheres}\n=4\pi r^2$

Therefore,

$T=u_cSc+u_hSh$

From the question

$u_h=2u_c$

The total cost becomes

$T=u_cSc+2u_cSh\n=2u_c \pi rh+8u_c \pi r^2$

We need to eliminate $h$ . The volume from the question gives a way out

$4640=(4)/(3)\pi r^3 +\pi r^2h\n\nh=(4640)/(\pi r^2)-(4r)/(3)$

substitute into the formula for total cost gives, after simplifying

$T=(16u_c\pi r^2)/(3)+(9280u_c)/(r^2)$

differentiating with respect to $r$ , we get

$(dT)/(dr)=(32)/(3)u_c\pi r-(9280u_c)/(r^2)$

at extrema

$(dT)/(dr)=0\n\n\implies (32)/(3)u_c\pi r=(9280u_c)/(r^2)\n\nr=\sqrt[3]{(870)/(\pi)}\approx 6.5ft$

To confirm that $r$ is a minimum value, carry out the second derivative test

$(d^2T)/(dr^2)=(32u_c\pi)/(3)+(18560)/(r^3)$

substituting $r=\sqrt[3]{(870)/(\pi)}$ , we get that $(d^2T)/(dr^2)$ > $0$ , confirming that minimum value

To find $h$ , recall that

$h=(4640)/(\pi r^2)-(4r)/(3)$

substituting $r$ , we get $h\approx 26.0ft$ as the corresponding minimum height

Therefore, $r\approx 6.5ft \text{ and } h \approx 26.0ft$ minimize the total cost of building the tank.

Learn more about minimizing dimensions to reduce costs here: brainly.com/question/19053049

Final answer:

The problem involves finding the dimensions of a cylinder and two hemispheres that minimize the cost to build an industrial tank of a specific volume. This involves setting up equations for the volume and cost, and then using calculus to find the dimensions that minimize the cost.

Explanation:

This problem can be solved using calculus. Let's denote the radius of both the hemispheres and the cylinder as r and the height of the cylinder as h. The total volume of the solid is the sum of the volume of the cylinder and the two hemispheres. Using the formulas for the volumes of a cylinder and hemisphere, we have:

V = (πr²h) + 2*(2/3πr³) = 4640 cubic feet.

The total cost of the material is proportional to the surface area. The surface area of the two hemispheres is twice as expensive as that of the sides of the cylinder, so we have:

Cost = 2*(2πr²) + πrh.

To minimize the cost, we can take the derivative of the Cost function with respect to r and h, set them equal to zero, and solve for r and h.

This problem involves calculus, the volume of cylinders and spheres, and optimization, which are topics covered in high school mathematics.

Learn more about Mathematics Optimization Problems here:

brainly.com/question/32199704

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For the function y=ln(x-1)+2 which of the following statements is truea. the domain is all real numbers and the range is [2, infinity)
b. the domain is (-1, infintity} and the range is all real numbers
c. the domain is (1, infinity) and the range is [2, infinity)
d. the domain is (1, infinity) and the range is all real numbers

Answers

For the function $y = ln(x-1) + 2$ , statement d is true. The domain is (1, ∞) and the range is all real numbers.

A function is an expression or a rule establishing a relationship between two sets or two variables, where one is independent and another is dependent.

The set of values you input into the data as the independent variable is called the domain of the function.

The set of possible outputs of the function, the dependent variable, is called the codomain of the function.

The set of elements part of the dependent variable that actually comes out of the function as output is called the range of the function.

Given function, $y = ln(x-1) + 2$

The domain of the function is what you can put into x.

for ln(x-1) to be defined, x-1 > 0 implies that x > 1

Thus the domain of function becomes (1, ∞).

The range of the function is what you get as y.

if 1 < x < 2, 0 < x-1 < 1, ln(x-1) < 0, thus $y = ln(x-1) + 2$ will have a value y < 2, maybe even negative.

if x = 2, x-1 = 1, ln(x-1) = ln(1) = 0, making y = 2

if x > 2, x-1 > 3, ln(x-1) > 0, making y >2.

Thus the range of function becomes (-∞, ∞).