HELP!!!! WILL MARK BRAINLIEST!!!!!!

Answers

Answer 1

Answer:

Answer: The answer is 9 because the equations represent the same expression but just in different forms.

Step-by-step explanation:

Related Questions

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Is 2+2 an equation or an expression and why?
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Sequencing of rigid motions matters . true or false ?

Answers

Answer:

False.......................

Step-by-step explanation:

Please mark as brainlist answers

which of the following expressions is equivalent to 20 - 4/5 x > (the > has a line under it) 16?

Answers

$20-(4)/(5)x\geq16\ \ \ \ |both\ sides\ -20\n\n-(4)/(5)x\geq-4\ \ \ \ |both\ sides\ :(-(5)/(4)) < 0\ then\ change\$

Solve the equation for y:
2x + 5y = 20

Answers

Answer:

y = $(20-2x)/(5)$

Step-by-step explanation:

Given

2x + 5y = 20 ( isolate the term in y by subtracting 2x from both sides )

5y = 20 - 2x ( divide both sides by 5 )

y = $(20-2x)/(5)$

The Answer will be y=4

What's the Discriminant of X^2-2X-15 ?

Answers

the discriminant is the secion inside the double parenthasees [()] below in the quadratic formulat which is
x= $\frac{-b+ \sqrt{[(b^(2)-4ac)]} }{2a}$

the determinant determines or tells whether the answer is real or imaginary
if it is negative, then it is imaginary, if positive, then it is real
so basically the discriminmant is $b^(2)-4ac$

so ax^2+bx+c
a=x^2-2x-15

a=1
b=-2
c=-15

subsitute
$-2^(2)-4(1)(-15)$ =4-4(1)(-15)=4+60=64
the discriminant is ( $-2^(2)-4(1)(-15)$ ) or 64

The current I in an electrical conductor varies inversely as the resistance R of the conductor. The current is 2 amperes when the resistance is 770 ohms. What is the current when the resistance is 808 ohms? Round your answer to two decimal places if necessary.

Answers

Answer: The value of the current is 1.91 A.

Step-by-step explanation:

From the question, the current I in an electrical conductor varies inversely as the resistance R of the conductor.

The equation can be written as,

$I=(K)/(R)$

Here, K is the proportionality constant and R is the resistance.

It is given in the problem that the current is 2 amperes when the resistance is 770 ohms.

Calculate the value of K by using above expression.

Put I= 2 A and R= 770 ohm.

$2=(K)/(770)$

$K=1540$

Calculate the value of the resistance when R= 808 ohms.

$I=(K)/(R)$

Put K= 1540 and R= 808 ohms.

$I=(1540)/(808)$

$I=1.91 A$

Therefore, the value of the current is 1.91 A.

1.9 amps hope it helps.

Use the functions f(x) = 3x – 4 and g(x) = x2 – 2 to answer the following questions. Complete the tables.

x f(x)–3–1 0 2 5

x g(x)–3–1 0 2 5

For what value of the what value of the domain {–3, –1, 0, 2, 5} does f(x) = g(x) {–3, –1, 0, 2, 5} does f(x) = g(x)? Answer:

consider the relation {(–4, 3), (–1, 0), (0, –2), (2, 1), (4, 3)}.Graph the relation.
State the domain of the relation. State the range of the relation. Is the relation a function? How do you know? Answer:

2. graph the function f(x) = |x + 2|.

Answer:

consider the following expression. Rewrite the expression so that the first denominator is in factored form. Determine the LCD. (Write it in factored form.) Rewrite the expression so that both fractions are written with the LCD. Subtract and simplify.

Answer:

Answers

$1)\nf(x)=3x-4\n|\ \ \ x\ \ \ |\ \ -3\ \ \ |\ \ -1\ \ \ |\ \ \ 0\ \ \ |\ \ \ 2\ \ \ |\ \ \ 5\ \ \ |\n=========================\n|\ f(x)\ |\ \ -13\ \ |\ \ -7\ \ |\ -4\ \ |\ \ \ 2\ \ \ |\ \ \ 11\ \ |\n\nf(-3)=3\cdot(-3)-4=-9-4=-13\nf(-1)=3\cdot(-1)-4=-3-4=-7\nf(0)=3\cdot0-4=0-4=-4\nf(2)=3\cdot2-4=6-4=2\nf(5)=3\cdot5-4=15-4=11$

$g(x)=x^2-2\n|\ \ \ x\ \ \ |\ \ -3\ \ \ |\ \ -1\ \ \ |\ \ \ 0\ \ \ |\ \ \ 2\ \ \ |\ \ \ 5\ \ \ |\n=========================\n|\ g(x)\ |\ \ \ \ \ 7\ \ \ \ |\ \ -1\ \ \ |\ -2\ \ |\ \ \ 2\ \ |\ \ \ 23\ \ |\n\ng(-3)=(-3)^2-2=9-2=7\ng(-1)=(-1)^2-2=1-2=-1\ng(0)=0^2-2=0-2=-2\ng(2)=2^2-2=4-2=2\ng(5)=5^2-2=25-2=23\n\nf(x)=g(x)\ \ \ \Leftrightarrow\ \ \ x=2,\ \ \ \ because\ \ \ \ f(2)=2\ \ \ and\ \ \ g(2)=2$

$2)\nthe\ relation:\ \{(-4, 3), (-1, 0), (0, -2), (2,1), (4, 3)\}.\n\nthe\ domain:\ D=\{-4,-1,0,2,4\}\nthe\ range:\ R=\{3,0,-2,1\}\n\nThis\ relation\ is\ the\ function,\ because\ \ each\ number\n of\ the\ domain\ D\ has\ exactly\ one\ value\ in\ the\ range\ R.$

$3)\nf(x)=|x+2|\n\n|x+2|= \left \{ {\big{x+2\ \ \ \ \ if\ \ \ x \geq -2} \atop \big{-x-2\ \ \ if\ \ \ x<-2}} \right.$

Answer:

-11 and 0 for EDGE2020

f(4)= -11

If g(x)=2, x= 0

Step-by-step explanation:

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