north. Find the magnitude of the
car's resultant vector.
Answer:
73.2km
Step-by-step explanation:
first you have to decompose 46 km into y and x components.
x=sin40°*46km
x=0.64*46km
x=29.44km
y=cos40°*46km
y=0.76*46km
y=34.96
now you add the y components together
32+34.96=66.98
finally use Pythagorean thereom to find the resultant vector.
a*a+ b*b=c*c
66.98*66.98+29.44*29.44=c*c
c*c= 4486.3+866.7
c=√5353
c=73.2 km this is the approximate value
Answer:
66 2/3 words per minute
Step-by-step explanation:
To convert 800 words in 12 minutes to a unit rate, you need to divide 800 and 12 by 12. Since 80012=2003=6623
12
800
=
3
200
=66
3
2
, then 800 words in 12 minutes = 6623words per minute
66
3
2
words per minute
.
(3x - 8) - (x2 - 5x - 2)
Answer:
-x^2 +8x -6
Step-by-step explanation:
Distribute the minus sign and collect terms.
(3x -8) -(x^2 -5x -2)
= 3x -8 -x^2 +5x +2
= -x^2 +8x -6
B.) At least 4 gallons and at most 6.5 gallons
C.) At least 2.5 gallons and at most 4 gallons
D.) Zhao Xue doesn’t have enough money left to buy any yofurt
Answer: The answer is (D). Zhao Xue doesn’t have enough money left to buy any yofurt
Step-by-step explanation: Given that Zhao Xue is buying buy milk and yogurt, a total of at least 6.5 gallons of dairy products and she has a budget of $20. The given graph represents the constraints on the number of gallons of milk 'M' and yogurt 'Y' Zhao Xue buys. Zhao Xue buys 4 gallons of milk. We need to calculate the number of gallons of yogurt she can buy to meet both her constraints.
From the graph, we can write
Condition A :
Condition B :
Now, if she buys 4 gallons of milk, the the conditions become
Here, there will be no solution to these constraints.
Therefore, she does not have enough money left to buy any yogurt.
Thus, the correct option is (D).
Answer: exactly 2.5 gallons
This is for khan academy.
Answer: 122.5
Step-by-step explanation: when it becomes 0.5 when rounding to the nearest whole number ot
Answer:
The volume of water that remains on the cone is 523.6 cm³
Step-by-step explanation:
To solve this problem you have to keep in mind the formules that describes the volume of a cone and the volume of a sphere.
Volume of a cone = (πr²h)/3
Volume of a sphere = (4/3)πr³
So, if the base of the cone has a diameter of 10 cm, its radius is 5 cm. Its altitude is 10 cm. ⇒Volume = (πr²h)/3 ⇒ Volume = [π(5²)10) ⇒
Volume = 785.4 cm³. This is the initial volume of water.
Now if the sphere fits in the cone and half of it remains out of the water, the other half is inside the cone. Estimating the volume of the sphere and dividing it by two, you find the volume of water that was displaced.
Volume of a sphere = (4/3)πr³, here the radius is the same of the base of the cone (5 cm).
⇒ Volume = (4/3)π(5³) ⇒ Volume = 523.6 cm³ ⇒ The half of this volume is 261.8 cm³. This is the volume of water displaced.
⇒ The volume of water that remains on the cone is 523.6 cm³ (785.4 cm³- 261.8 cm³)