Answer:
The patient requires a dose of 107.2 mg of gentamicin
Explanation:
A dosage of 1.75 mg per Kilogram body weight results in blood serum levels of 4.5 mcg/mL
This means that; 1.75 mg/ kg = 4.0 mcg/mL
Therefore, dosage of gentamicin in mg/kg that will result in 4.5 mcg/mL blood serum level = (1.75 mg/Kg * 4.5 mcg/mL) / 4.0 mcg/mL
Dosageof gentamicin = 1.97 mg/Kg
1-lb = 0.453592 Kg
Weight of 120-lb patient in Kg = 120 * 0.453592 = 54.43 Kg
Dose in mg required by patient = 1.97 mg/Kg * 54.43 Kg = 107.2 mg
Therefore, the 120-lb patient requires a dose of 107.2 mg of gentamicin to result in a blood serum level of 4.5 mcg/mL
Answer: In order to a solute to dissolve in a solvent, both the attraction forces that bind the units of solute together and the intermolecular forces that bind the molecules of solvent together must be weaker than the attraction forces between the particles of solute and the molecules of solvent.
Explanation:
The solute particles in are binded together in virtue of attractive forces (the nature and strength of these forces depends on the particular solute).
The same happens with the solvent molecules: they are binded by attractive forces (similarly, the nature and strength of these forces depend on the particular solvent).
To get dissolved (form solution) the particles of solute must be separated and mixed with the solvent particles in a process called solvatation.
The solute particles must surrounded by the solvent particles.
When the forces of attraction between the solute particles and the solvent are stronger than the forces of attraction that bind the solute particles, the solute particles move away from the solid solute and are integrated into the solution.
CH4 + 3O2 yields CO2 + 2H2O
Al4C3 + 3H2O yields CH4 + 4Al(OH)3
Zn + 2HCl yields ZnCl2 + H2
Answer:
Molarity of NaOH solution is 1.009 M
Explanation:
Molar mass of HCl is 36.46 g/mol
Number moles = (mass)/(molar mass)
So, 0.8115 g of HCl = HCl = 0.02226 moles HCl
1 mol of NaOH neutralizes 1 mol of HCl.
So, if molarity of NaOH solution is S(M) then moles of NaOH required to reach endpoint is
So,
or, S = 1.009
So, molarity of NaOH solution is 1.009 M
Answer:
1.3005 M
Explanation:
Given that:
Mass of NaCl = 76 g
Molar mass of NaCl = 58.44 g/mol
The formula for the calculation of moles is shown below:
Thus,
Given that volume = 1 L
Considering:
Molarity = 1.3005 M