Height of cannon 5 m, initial speed of projectile 15m/s, angle of launch 0 degrees. What is the range and time in the air? Please show work!

Answers

Answer 1

Answer:

Answer:

The range is 15.15 m and the time in the air is 1.01 s

Explanation:

Horizontal Motion

When an object is thrown horizontally (with angle 0°) with a speed v from a height h, it follows a curved path ruled exclusively by gravity until it eventually hits the ground.

The range or maximum horizontal distance traveled by the object can be calculated as follows:

$\displaystyle d=v\cdot\sqrt{\frac {2h}{g}}$

To calculate the time the object takes to hit the ground, we use the equation below:

$\displaystyle t=\sqrt{(2h)/(g)}$

The cannon is shot from a height of h=5 m with an initial speed of v=15 m/s. The range is calculated below:

$\displaystyle d=15\cdot\sqrt{\frac {2*5}{9.8}}=15*1.01$

d = 15.15 m

The time in the air is:

$\displaystyle t=\sqrt{(2*5)/(9.8)}$

t = 1.01 s

The range is 15.15 m and the time in the air is 1.01 s

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What is an earthquake?

Answers

an earthquake is when two tectonic plate merge and one snaps up suddenly, causing the plate to shake violently until it settles back into place. hope i helped :3

1
Verify the identity. Show your work.

cot θ ∙ sec θ = csc θ

Answers

To verify the identity, we can make use of the basic trigonometric identities:
cot θ = cos θ / sin θ
sec θ = 1 / cos θ
csc θ = 1 / sin θ

Using these identities:
cot θ ∙ sec θ = (cos θ / sin θ ) ( 1 / cos θ)

We can cancel out cos θ, leaving us with
cot θ ∙ sec θ = 1 / sin θ
cot θ ∙ sec θ = = csc θ

What is the acceleration of a 6.4 kilogram bowling ball if a force of 12 N is applied to it?

Answers

F=ma
12=6.4a
1.875=a
A=1.875

Answer:

1.875 m/sec2

Explanation:

Acceleration = Force/Mass

Acceleration = 12/6.4

12/6.4 = 1.875

Units = m/sec2

1875 m/sec2

Simone created a chart to summarize the energy transformations that take place when energy from the wind is used to generate electricity.Which best completes the chart?

nuclear energy transformed to electrical energy

chemical energy transformed to electrical energy

radiant energy transformed to mechanical energy

kinetic energy transformed to mechanical energy

Answers

Kinetic energy transformed to mechanical energy. The object that is being rotated by the wind gains kinetic energy and the motor, that is connected to the rotating object, gains mechanical energy.

The mechanical energy gained will be transformed into electrical energy once the set up starts to be used for generating electricity.

Answer:

kinetic energy transformed to mechanical energy or D

Explanation:

got it right on edge 2022!

The speed of a wave is determined by multiplying the wavelength by the frequency

Answers

Wellll . . . that's not a very easy way to do it. You'd still need
to figure out a way to measure the wavelength AND a way to
measure the frequency, so you won't find many engineers
actually trying to determine the wave speed by doing all of that.

But your statement is correct. The product of

(wavelength) times (frequency)

IS the speed of the wave.

At what distance from a long, straight wire carrying a current of 8.7 A is the magnetic field due to the wire equal to the strength of Earth’s field, approximately 5.4 × 10−5 T? The permeabilty of free space is 1.25664 × 10−6 T · m/A. Answer in units of cm.

Answers

Answer:

r= 3.2 cm

Explanation:

Given that

I= 8.7 A

B= 5.4 x 10⁻⁵ T

μo=1.25664 x 10⁻⁶

We know that magnetic filed in wire at a distance r given as

$B=(\mu_oI)/(2\pi r)$

$r=(\mu_oI)/(2\pi B)$

By putting the values

$r=(1.25664* 10^(-6)* 8.7)/(2* \pi * 5.4* 10^(-5))\ m$

r=0.032 m

r= 3.2 cm

Final answer:

The distance from a long straight wire at which the magnetic field equals the strength of Earth’s field, given a current of 8.7 A and Earth's field of 5.4 × 10−5 T, can be calculated using the formula for the magnetic field around a current-carrying wire. Substituting the given values, the answer is approximately 37.22 cm.

Explanation:

To solve this physics problem, we will use the formula for the magnetic field produced by a current carrying long, straight wire. The formula is: B = μI / (2πr), where 'B' is the magnetic field strength, 'μ' is the permeability of free space, 'I' is the current, and 'r' is the radial distance away from the wire.

In this case, Earth’s magnetic field, 'B', is given as 5.4 × 10−5 T, the current, 'I', is given as 8.7 A, and the permeability of free space, 'μ', is given as 1.25664 × 10−6 T · m/A. We need to find 'r', the distance away from the wire, and we want this answer in centimeters.

So, rearrange the formula to solve for 'r': r = μI / (2πB).

Substitute our known values into the equation: r = (1.25664 × 10−6 T · m/A × 8.7 A) / (2π × 5.4 × 10^-5 T). After calculating, we need to convert from meters to centimeters by multiplying by 100. The final answer is approximately 37.22 cm.

Learn more about Magnetic Field Calculation here:

brainly.com/question/30758042

#SPJ3

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