The quotients of 80,000 divided by 2,000, 200, and 20 differ because of the magnitude of the divisor. The quotient is larger when the divisor is smaller.
The difference in the quotients of 80,000 divided by 2,000, 200, and 20 comes from the magnitude of the divider. The larger the divider, the smaller the quotient.
If you divide 80,000 by 2,000, the quotient is 40. When you divide 80,000 by 200, the quotient is 400. Lastly, if you divide 80,000 by 20, the quotient is 4,000. Hence, the quotients are different because of the different divisor values in each operation. The smaller the divisor, the larger the quotient gets.
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Answer:
A and D would be the correct answers
Step-by-step explanation:
A. (x-9)(x-1)
B. (x+9)(x+1)
C. Prime
D. (x+9)(x-1)
x^2 − 8x + 9
What two numbers when multiplied yield 9 but when added yield -8?
There are no such numbers.
Use the quadratic formula.
B.{(–4, 1), (–2, 3), (–2, 1), (–1, 5), (3, 2)}
C.{(–4, 1), (–2, 3), (–1, 2), (3, 5), (3, 2)}
D.{(–4, 1), (–2, 3), (–1, 1), (–1, 5), (3, 2)}
3y − x = 4
graph of two lines that intersect at the point (negative 1, 1)
graph of two lines that intersect at the point (1, 1) < Not
graph of two parallel lines with positive slopes
None of the above
Answer: Graph of two lines that intersect at the point (negative 1, 1).
Step-by-step explanation:
The given system of linear equations :
Multiply equation (1) by 3 , we get
Subtract equation (2) from (3), we get
Divide both sides by 7 , we get
x=-1
Put value of x in (1), we get
⇒ both lines are intersecting at (x,y)=(-1,1)
∴ The correct graph of the given system of equations : graph of two lines that intersect at the point (negative 1, 1)
Answer:
(-1,1) One solution
Step-by-step explanation:
Use these steps for the equations:
1) Rewrite the equation in slope intercept form.
2) Graph the first equation.
3) Graph the second equation.
4) Identify the point of intersection.
A=38,37,32
B=40,51,62
C=39,49,59
D=38,47,56