Answer: Helium is least likely to form bonds.
Explanation:
Helium has the electronic configuration . As the 1s sub-shell is completely filled so there is no need for helium to form bonds with other atoms.
Whereas, nitrogen has the electronic configuration . As the p sub-shell is half filled, it has the tendency to accept more electrons. Therefore, nitrogen is more susceptible to form bonds as compared to helium.
Thus, it is concluded that helium is least likely to form bonds.
The atomic number of an atom is determined by the number of protons present in the atom that is the atomic number and number of protons are same for an atom. It is unique for every atom.
Atomic mass: It is nearly equals to the sum of mass of subatomic particles present in the atom that is sum of proton and neutron.
Number of neutrons: in an atom, the number of neutrons are always equal to the number of protons. If the number of neutrons are different for a number of proton then it is said be an isotope of that atom.
Protons plus neutrons: Sum of number of protons and number of neutrons is said to be the mass number of that atom.
Hence, the atomic number is the number of protons.
Answer:
The answer to your question is: 1, 2, 1, 2
Explanation:
1 Fe(s) + 2 Na⁺(aq) → 1 Fe²⁺(aq) + 2 Na(s)
Fe⁰ - 2e⁻ ⇒ Fe⁺² Oxidases
Na⁺ + 1 e⁻ ⇒ Na⁰ Reduces
1 x ( 1 Fe⁰ ⇒ 1 Fe⁺²) Interchange number of
2 x ( 2Na⁺ ⇒ 2 Na⁰ ) electrons
To balance the oxidation-reduction reaction Fe(s) + Na+(aq) → Fe2+(aq) + Na(s), follow these steps: balance atoms other than hydrogen and oxygen, balance hydrogen atoms, balance oxygen atoms, verify charges
To balance the oxidation-reduction reaction Fe(s) + Na+(aq) → Fe2+(aq) + Na(s), we need to balance the number of atoms for each element and the total charge on both sides of the reaction. Here's the step-by-step process:
So, the balanced oxidation-reduction reaction is: Fe(s) + 2Na+(aq) → 2Fe2+(aq) + Na(s).
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How much CaCl2, in grams, is needed to make 2.0 L of a 3.5M solution?
greater molecular size of water
2.
stronger hydrogen bonding in water
3.
higher molarity of water
4.
larger gram-formula mass of water
has higher boiling point than , as there has been stronger hydrogen bonding in . Thus, option 2 is correct.
The boiling point has been the temperature at which the liquid has been converted to the gaseous form. The boiling point has been based on the intemolecular attractions between the atoms.
Based on the intermolecular interactions, the compound with higher intermolecular force required more energy to break the bond and change the state, and thus have high boiling point.
The hydrogen sulfide and water has hydrogen bonding. The hydrogen bonding has been based on the electronegativity of the atom involved. The more electronegative atom, stronger will be hydrogen bonding and thereby higher boiling point.
In and , the oxygen has been more electronegative than sulfur and thus results in stronger hydrogen bonding.
Thus, has higher boiling point than , as there has been stronger hydrogen bonding in . Thus, option 2 is correct.
Learn more about boiling point here:
Answer:
2, stronger hydrogen bonding
Explanation:
a. the concentration of b-galactosidase
b. the concentration of Luria Broth
c. the concentation of glucose
d. the concentration of lactose
e. the concentration of ONPG
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Answer:
a. The concentration of β-galactosidase
Explanation:
β-Galactosidase is an enzyme that hydrolyzes ß-D-galactosides like lactose to glucose and galactose.
It also cleaves o-nitrophenyl-β-D-galactoside (ONPG) to yield galactose and o-nitrophenol, which is yellow, and can be measured by its absorption at 420 nm.
If the concentration of ONPG is greater than that of β-galactosidase, the concentration of o-nitrophenol produced is proportional to the concentration of the enzyme.