What is a type of percent that compares the final amount and original amounts?
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Can someone tell me if the following steps in the correct order or where I went wrong? In experimental studies, we follow a logical method to arrive at a conclusion. Arrange the given steps in the correct sequence. State a problem Make Hypothesis perform an experiment to collect data. Ask relevant questions Arrival at a logical conclusion. Compare with the baseline value of the control group. should I switch the last two around?
Witch is greater 140% or 0.14
Whats the unit rate of 750 yards in 25 minutes
2 The density of a substance can be determinedby finding the unit rate that compares mass tovolume. A nugget of gold has a mass of463.2 grams and a volume of 24.0 milliliters.What is the density of gold?F 11,116.8 g/mLG 439.2 g/mLH 0.052 g/mLJ 19.3 g/mL
280z - 25y - 30
PLS ASAP
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Answer:
Step-by-step explanation:
Forst step is finding a common factor, you can do this easily by looking at the ones digit. All 3 values end in 0 or 5, so a factor is definately 5.
We now divide all values by 5.
Once you get a prime number after factoring, that is the GCF, Greatest Common Factor. We can make an equation like what is below to show oir factored answer.
4(x2 + 4x)
x(4x + 16)
4x(x + 4)
Prime
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Answer:
The answer is C
Step-by-step explanation:
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2) 20.3 meters
3) 101.3 meters
4) 202.6 meters
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C squared = 4.5 squared + 9 squared
C squared = 20.25 + 81
C squared = 101.25
Square root 101.25 you get 10.06 round up and you get the answer to be number 1
According to the pythagora theorum,
h² = a² + b²
h² = 4.5² + 9²
= 20.25 + 81
thus, h² = 101.25
thus, h = √101.25
thus, h = 10.06230589 units, or 10.1 rounded to the nearest tenth
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Answer:
THERE
Step-by-step explanation:
a) To determine how far each ostrich ran, we need to calculate the area under the velocity-time graph for each ostrich. Since the graph represents velocity, the area under the graph represents the distance traveled.
For Ostrich Bert:
The area under the graph can be divided into two sections: a triangle and a rectangle. The triangle's base is 3 seconds and its height is 18 m/s, so its area is (1/2) * 3 * 18 = 27 m. The rectangle has a base of 2 seconds and a height of 9 m/s, so its area is 2 * 9 = 18 m. Adding the areas together, Bert ran a total distance of 27 + 18 = 45 meters.
For Ostrich Ernie:
The area under the graph can also be divided into two sections: a triangle and a rectangle. The triangle's base is 4 seconds and its height is 12 m/s, so its area is (1/2) * 4 * 12 = 24 m. The rectangle has a base of 2 seconds and a height of 6 m/s, so its area is 2 * 6 = 12 m. Adding the areas together, Ernie ran a total distance of 24 + 12 = 36 meters.
b) To calculate the average velocity of Bert, we need to divide the total distance he ran (45 meters) by the total time it took (5 seconds). Therefore, Bert's average velocity is 45 meters / 5 seconds = 9 m/s.
c) The initial acceleration of Ernie can be determined by finding the slope of the velocity-time graph during the initial portion. From the graph, we can see that Ernie's velocity increases by 6 m/s over the first 2 seconds. Therefore, his initial acceleration is (change in velocity) / (change in time) = 6 m/s / 2 seconds = 3 m/s^2.
d) Without further calculation, we can determine that Ernie had the greatest initial acceleration. This is because Ernie's velocity increases at a steeper slope during the initial part of the graph compared to Bert's velocity. The greater the slope, the greater the acceleration. Therefore, Ernie had the greatest initial acceleration.