How does increasing the tension of a spring affect a wave on the spring?

Answers

Answer 1

Answer: Increasing the tension of a spring affects a wave on the spring because it increases the frequency. When the tension rises, so does the frequency.

Answer 2

Answer:

Answer: Increases the frequency of the wave

Explanation:

Increasing the tension of a spring means increasing its stiffness. The wave produced thereafter has greater frequency.

Higher tension causes the spring to have greater restoring force causing it to quickly come back to its equilibrium position. Thus, the speed of the wave also increases.

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Centripetal acceleration occurs because an object isSelect one:
a. slowing down.
b. changing direction.
c. speeding up.
d. none of these choices.

Answers

Answer:

changing direction

............

A is a process that involves reactants and products

Answers

I think the answer is chemical reactions.

Can someone give me the answer for this? thanks. (The questions in the picture)

Answers

Answer: I would think it would be Ionic/synthesis

Explanation: Because the calcium gives up an electron to every chlorine atom resulting in Ca +.

A wave creates a strong undertow

Answers

Hey there!

Answer: A swell

A wave which creates a strong undertow is called a swell. These types of waves are also known as surface gravity waves.

Thank you!

If 20 beats are produced within one second, which of the following frequencies could possibly be held by two sound waves traveling through a medium along a common path at the same time? A. 38 Hz and 63 Hz
B. 22 Hz and 42 Hz
C. 47 Hz and 55 Hz
D. 18 Hz and 26 Hz

Answers

Answer:

B. 22 Hz and 42 Hz

Explanation:

The beat is an interference pattern which occurs when two waves of slightly different frequencies meet each other. The beat is heard as a periodic variation, whose frequency (called beat frequency) is equal to the absolute value of the difference between the frequencies of the individual waves:

$f_B = |f_1-f_2|$

In this problem, we are told that 20 beats per second are produced, so the beat frequency is

$f_B = 20 s^(-1) = 20 Hz$

Therefore, we must find the two waves which have a difference in frequency equal to this value, 20 Hz. Let's see each choice:

A. 38 Hz and 63 Hz --> $f_B = |38 Hz-63 Hz|=25 Hz$ --> NO

B. 22 Hz and 42 Hz --> $f_B = |22 Hz-42 Hz|=20 Hz$ --> YES

C. 47 Hz and 55 Hz --> $f_B = |47 Hz-55 Hz|=8 Hz$ --> NO

D. 18 Hz and 26 Hz --> $f_B = |18 Hz-26 Hz|=8 Hz$ --> NO

So, the correct choice is

B. 22 Hz and 42 Hz

The right answer for the question that is being asked and shown above is that: "B. 22 Hz and 42 Hz." If 20 beats are produced within one second, the frequencies that could possibly be held by two sound waves traveling through a medium along a common path at the same time is B. 22 Hz and 42 Hz

A spring is stretched 0.75 m by using a force of 30 N. What is the spring constant

Answers

Hi there!

40 N/m

We can use Hooke's Law:

F = kx or F = -kx

F = force (N)

k = Spring constant (N/m)

x = displacement (m)

We are given the force and displacement, so:

F/x = k

30/0.75 = 40 N/m

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