A rectangular barge 7 m long and 2 m wide floats in fresh water. How much will the barge sink when loaded with 600 kg of sand? Show all calculations leading to an answer.

Answers

Answer 1

Answer: You must apply Archimides' principle.

The barge will sink until the sum of the forces on it equals zero.

The two forces are the weight of the barge (with sand) and the buoyancy force, the force exerted by the liquid (fresh water) on the barge.

Then, weight of the barge with sand = m*g = 600 kg * g

Buoyancy force = density of the fluid * Volume of displaced fulid * g

Then, m*g = density of the fulid * Volume of displaced fluid * g

m*g = df * Vf * g

m = df*Vf => Vf = m/df = 600 kg / 1 000 kg/m^3 = 0.6 m^3

The volume of the displaced fluid equals the volume of the portion of the barge sinked, wich is the area of the rectangular base times the depth to which it sinked>

7m*2m*H = 0.6 m^3 => H = 0.6 m^3 /[14 m^2] = 0.043 m = 4.3 cm

Answer: 4.3 cm

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A trombone has a variable length. When a musician blows into the mouthpiece and causes air in the tube of the horn to vibrate, the waves set up by the vibrations reflect back and forth in the horn to create standing waves. As the length of horn is made shorter, what happens to the frequency?A) The frequency will increase or decrease depending on how hard the horn player blows.
B) The frequency will increase
C) The frequency will decrease
D) The frequency will increase or decrease depending on the diameter of the horn.
E) The frequency will remain same

Answers

Answer:

B) The frequency will increase

Explanation:

The length of the instrument is given by

$L=(\lambda)/(2)\n\Rightarrow \lambda=2L$

Wavelength is given by

$\lambda=(v)/(f)$

$(v)/(f)=2L\ or\ L\propto (1)/(f)$

It can be seen that the length is inversely proportional to the frequency.

Here, the length of the trombone is decreasing so the frequency will increase.

Question 17 options:A 71.8 kg man goes from an area where the acceleration due to gravity is 9.79 m/s2 to an area where the acceleration due to gravity is 9.82 m/s2.What is the change (in kilograms), to the mass of the man? Respond to three significant digits expressed as a.bc and remember to record your responses for a, b, and c in that order.(i was thinking the answer would be 0 but im not sure)

Answers

Mass doesn't change, no matter where you take it.
Your first impression of ' 0 ' is totally correct.

a truck travels up a hill with a 13.0 ◦ incline. the truck has a constant speed of 21.0 m/s. what is the horizontal component of the truck’s velocity?

Answers

Answer:

20.46m/s

Explanation:

$21 * \cos(13) = 20.46$

In a nuclear reactor, the moderator is: usually made of graphite placed between the fuel rods used to slow down neutrons all of the above none of the above

Answers

The correct answer is all of the above. In a nuclear reactor, the moderator is usually made of graphite, placed between the fuel rods, and used to slow down neutrons. The nuclear moderator is a medium in which reduces the speed of the fast neutrons.

The answer is D. All the above

The second law of thermodynamics states that whenever energy changes occur, __________ always increases.

Answers

The second law of thermodynamics states that whenever energy changes occur, DISORDER always increases.

Final answer:

The Second Law of Thermodynamics states that entropy, which represents the disorder or randomness in a system, always increases when energy changes occur. An example would be heat dispersing from a hot drink into the environment.

Explanation:

The Second Law of Thermodynamics states that whenever energy changes occur, entropy always increases. Entropy refers to the degree of disorder or randomness in a system. Thus, the law is essentially asserting that natural processes tend towards chaos or disorder. For example, if we consider a cup of hot coffee left on a table, with time, the heat (energy) from the coffee disperses into the surrounding environment, leading to an increase in entropy. This concept applies universally in closed systems, where energy cannot enter or leave.

Learn more about Second Law of Thermodynamics here:

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In the mobile m1=0.42 kg and m2=0.47 kg. What must the unknown distance to the nearest tenth of a cm be if the masses are to be balanced? The answer is 13.4 In the mobile what is the value for m3 to the nearest hundredth of a kilogram?

Answers

Complete Question

The complete question is shown on the first uploaded image

Answer:

Explanation:

From he question we are told that

The first mass is $m_1 = 0.42kg$

The second mass is $m_2 = 0.47kg$

From the question we can see that at equilibrium the moment about the point where the string holding the bar (where $m_1 \ and \ m_2$ are hanged ) is attached is zero

Therefore we can say that

$m_1 * 15cm = m_2 * xcm$

Making x the subject of the formula

$x = (m_1 * 15)/(m_2)$

$= (0.42 * 15)/(0.47)$

$x = 13.4 cm$

Looking at the diagram we can see that the tension T on the string holding the bar where $m_1 \ and \ m_2$ are hanged is as a result of the masses ( $m_1 + m_2$ )