What is a simpler form of the radical expression? sqrt 36g^6 A. 36|g^3| B. 36g^4 C. 6|g^3| D. 6g^4
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Answer:
Lesson 1 Unit 2: Roots and Radical Expressions
1 = a (no real root)
2 = c (-0.05)
3 = c (6lg^3l)
4 = d (5x^7y^8)
5 = a (3x^2/5y)
5/5 100%
Step-by-step explanation:
We notice that 36 is a square of 6 so we write:
Now, square root we imply on each of factors (g^6 and 6 ^2)
we get.
6*|g^3|
The reason for absolute value is because of variable g.
Answer is C.
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I need help good explanation and answer for more points
Will award Brainliest Chloe is buying souvenirs on vacation. She wants to spend $70 at most, but only has 60cubic inches of space available in her luggage. If bracelets cost $7 and take up 3 in of spaceand t-shirts are $5 but take 15 in of space, write a system of four inequalities thatmodel Chloe's possible purchases. Let x = number of bracelets and y = number of t-shirts;
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needs at least average of 70
at least is represented as greater than or equal to or the sign (>)
70>(total)/(number oftests)
since we have 3 tests, we have to have 3 scores so
70>(x+y+z)/3
he scored 85 and 60
70>(x+85+60)/3 (doesn't matter which to subsitute)
70>(x+145)/3
multiply obht sides by 3
210>x+145
subtract 145 from both sides
65>x
he needs to get at leas 65 on his third test
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Answer:
(1,1)
Step-by-step explanation:
use the midpoint formula to find the midpoint of the line segment
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Answer: x=15
Step-by-step explanation: THIS IS THE CORRECT ANSWER
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Answer: 116.937
I hope this helped!
Answer: The answer is 116.937
Hope it helped :D
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The power utilised by frank in the month of march is 470 kilowatts - per hour.
What is an expression?
The mathematical expression combines numerical variables and operations denoted by addition, subtraction, multiplication, and division signs.
Mathematical symbols can be used to represent numbers (constants), variables, operations, functions, brackets, punctuation, and grouping. They can also denote the logical syntax's operation order and other properties.
Given that Franks's electric bill for the month of March was $85.78. The electric company charged a flat monthly fee of $20.00 for service plus $0.14 per kilowatt-hour of electricity used.
The equation will be written as,
B = 20 + 0.14K
85.78 = 20 + 0.14k
k = ( 80.78 - 20 ) / 0.14
K = 65.78 / 0.14
K = 470 Kilowatt-hour
Therefore, the power utilised by frank in the month of march is 470 kilowatts - per hour.
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Answer:
I got 469.8 kilowatt-hours. I got this by taking the total of Frank's bill, which was $85.78, and subtracting the flat monthly fee of $20.00. I did this because I need to find out the number of kilowatt-hours Frank used. Then, I divided $65.78 by $0.14 since that is the price per kilowatt-hour and got about 469.8 kilowatt-hours used by Frank.
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y( 3y - 4)
Greatest common factor: y