Find the coordinates for the midpoint of the segment with endpoints given. (5, 6) and (8, 2)

Answers

Answer 1
Answer: we first introduce midpoint formula
X1+X2 over 2;Y1+Y2 over 2
5+8 over 2 ; 6+2 over 2
x=13 over 2 ; Y=4
therefore midpoint=(13/4;4)

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3t<-15 a. t<-5 b. t>-5 c. t<-45 d. t>-45

Answers

3t<-15 solve for t

divide both sides by 3
3t/3 < -15/3

Simplify
t < -5

Anser is 
a. t<-5
If 3t < -15 all you need to do is divide by 3 on both sides, 

t < -5

One plant from the garden is randomly selected. There is a 30% chance that the plant was purchased this year, and there is a 6% chance that the plant was purchased this year and produces berries. What is the probability that the chosen plant does NOT produce berries, given that the plant was purchased this year? Write the probability as a percent. Round to the nearest tenth if needed. ____________%

Answers

Answer and workings in the attachment below. Also, do me one big favour. Let me know if it's the answer your teacher or text book ends up giving you. That would give me some satisfaction.

Answer: 80%

Can anyone help know if this is right if not what is the right answer?

Answers

We will use the Sine Ratio to solve for A:

Sin(A) = Opposite / Hypotenuse
Sin(A) = 12 / 15
Sin(A) = 0.8  (Take the Inverted Sin of this number) 
∠A = 53.13°

Therefore, ∠A = 53.13°


What two numbers multiply to 10 and add to -29 ?

Answers

xy=10
x+y=29

subtract x from both sides for second equation

y=-x-29
subsitute in second equaiton
x(-x-29)=10
-x^2-29x=10
add x^2+29x to both sides
x^2+29x+10=0
quadratic formula
if you have
ax^2+bx+c=0,
x=\frac{-b+/- \sqrt{b^(2)-4ac} }{2a}

so
x^2+29x+10=0
a=1
b=29
c=10
x=\frac{-29+/- \sqrt{(-29)^(2)-4(1)(10)} }{2(1)}
x= (-29+/- √(841-40) )/(2)
x= (-29+/- √(801) )/(2)
x= (-29+/- 3√(89) )/(2)

x= (-29- 3√(89) )/(2) or (-29+ 3√(89) )/(2)
those are the 2 numbers
aprox=-28.65 and -0.349


There are none. 
You can prove this by graphing. 
xy = 10
y = 10/x

x + y = -29
y = -x - 29

On the graphing calculator, type in
Y1 = 10/x
Y2 = -x - 29

As you can see the two do not intersect.

An order of 12 dozen rollerball pens and 5 dozen ballpoint pens cost $116. A later order 8 dozen rollerball pens and 12 dozen ballpoint pens cost $112. What was the cost of 1 dozen of pens?And how much does 1 dozen pencils cost?

Answers

r=cost per dozen rollerball pens
b=cost per dozen ballpoint pens
p=cost per dozen pencils
???

ignore pencils

12r+5b=116
8r+12b=112

eliminate
simplify last equation by dividing by 4
2r+3b=28

eliminate r's
multiply 2r+3b=28 by -6 and add to top equation

-12r-18b=-168
12r+5b=116 +
0r-13b=-52

-13b=-52
divide both sides by -13
b=4

plug back in
2r+3b=28
2r+3(4)=28
2r+12=28
minus 12
2r=16
divide by 2
r=8



ballpoint=pencils

1dozen pencils=$4
1dozen rollerbladepens=$8

There are 21 students in Mrs. Callan's class. There are 14 students in her class that got an A on the last spelling test. In simplest form, what fraction of Mrs. Callan's class got an A on the last spelling test?

Answers

14 students in 21 student got an A on the test so 14/21 people got A. the numerator and the denominator are both divisible by 7 so the simplest form of this fraction would be 2/3