Find the equation of the line through (-4,6) that is parallel to the line y=-5x+2

Answers

Answer 1
Answer:

Answer:

The equation of the line, using the point-slope form, through (-4,6) that is parallel to the line will be:

y=-5x-14

Step-by-step explanation:

We know that the slope-intercept form is

y=mx+b

Where m is the slope and b is the y-intercept

Given the equation

y=-5x+2

comparing with the slope-intercept form

slope = m = -5

y-intercept = b = 2

We know that the parallel lines have the same slopes.

so, the slope of the parallel line will be: -5

Thus, the equation of the line, using the point-slope form, through (-4,6) that is parallel to the line will be:

y-y_1=m\left(x-x_1\right)

y-6 = -5(x-(-4)

y-6 = -5 (x+4)

y-6 = -5x-20

y=-5x+6-20

y=-5x-14

Answer 2
Answer:

Answer:

y=-x+2

Step-by-step explanation:

i already did it and your welcome in advance


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A number is divisible by 3 if the sum of the digits of the number is divisible by 3.

Answers

I believe the answer the the question A number is divisible by 3 if the sum of the digits of the number is divisible by 3. Is 504, it makes sense

Let h be the function given by h(x) =x+x-2
²-1
We will investigate the behavior of
both the numerator and denominator of h(x) near the point where x = 1. Let
f(x)= x³ + x -2 and g(x)=x²-1. Find the local linearizations of f and g at a = 1,
and call these functions Lf(x) and Lg(x), respectively.
Lf(x) =
L₂(x) =
Explain why h(x) ≈
Lf(x)
Lg(x)
for a near a = 1.

Answers

Final answer:

The local linearizations of f(x) and g(x) at a = 1 are Lf(x) = 4x - 5 and Lg(x) = 2x - 2 respectively. The function h(x) ≈ Lf(x)/Lg(x) because the local linearizations provide a good approximation of the numerator and denominator of h(x) near x = 1.


Explanation:

The local linearization of a function at a given point is an approximation of the function using a linear equation. To find the local linearization of a function f at a = 1, we need to find the slope of the tangent line at a = 1, which is equivalent to finding the derivative of f at x = 1. By taking the derivative of f(x) = x³ + x - 2, we get f'(x) = 3x² + 1. Evaluating f'(1), we find that the slope of the tangent line at a = 1 is 4. Therefore, the local linearization of f at a = 1, denoted as Lf(x), is given by Lf(x) = f(a) + f'(a)(x - a), which becomes Lf(x) = -1 + 4(x - 1) = 4x - 5.

Similarly, to find the local linearization of g(x) = x² - 1 at a = 1, we need to find the slope of the tangent line at a = 1. The derivative of g(x) is g'(x) = 2x. Evaluating g'(1), we find that the slope of the tangent line at a = 1 is 2. Therefore, the local linearization of g at a = 1, denoted as Lg(x), is given by Lg(x) = g(a) + g'(a)(x - a), which becomes Lg(x) = 0 + 2(x - 1) = 2x - 2.

When investigating the behavior of the function h(x) = (f(x))/(g(x)) near the point x = 1, we can approximate h(x) using the local linearizations of f and g at a = 1. Near the point a = 1, h(x) ≈ Lf(x)/Lg(x) because Lf(x) and Lg(x) provide a good approximation of the numerator and denominator, respectively, of h(x). This approximation holds as long as x is close to 1.


Learn more about local linearizations of functions here:

brainly.com/question/34258619


Which represents an exterior angle of triangle XYZ?O LXZ
O JXM
O JXZ
O HXJ

on edge 2020

Answers

An exteriorangle of ΔXYZ is ∠HXJ.

The correct option is D.

What is an angle measure?

When two lines or rays intersect at a single point, an angle is created. The vertex is the term for the shared point. An angle measure in geometry is the length of the angle created by two rays or arms meeting at a common vertex.

As per the provided diagram, the exterior angles in the ΔXYZ are:

∠LXH,

∠MXJ,

∠HXJ,

∠OYK,

∠GZN,

∠MXZ,

∠YXL,

∠KYZ,

∠GZY.

From the given choices, ∠HXJ is an exterior angle of ΔXYZ.

To learn more about the angle measure;

brainly.com/question/14684647

#SPJ7

Answer:

The answer is C, <JXZ.

Step-by-step explanation:

Help pls algebra I nood help pls

Answers

Answer:

I think it's c

Step-by-step explanation:

4 times 3x equals 12x and 4 times 4x is 16x

It’s c have an nice day

lim x rightarrow 0 1 - cos ( x2 ) / 1 - cosx The limit has to be evaluated without using l'Hospital'sRule.

Answers

Answer with Step-by-step explanation:

Given

f(x)=(1-cos(2x))/(1-cos(x))\n\n\lim_(x \rightarrow 0)f(x)=\lim_(x\rightarrow 0)(\frac{1-(cos^2{x}-sin^2{x})}{1-cos(x)})\n\n(\because cos(2x)=cos^2x-sin^2x)\n\n\lim_(x \rightarrow 0)f(x)=\lim_(x\rightarrow 0)((1-cos^2x)/(1-cos(x))+(sin^2x)/(1-cosx))\n\n=\lim_(x\rightarrow 0)(((1-cosx)(1+cosx))/(1-cosx)+(sin^2x)/(1-cosx))\n\n=\lim_(x\rightarrow 0)((1+cosx)+(sin^2x)/(1-cosx))\n\n\therefore \lim_(x \rightarrow 0)f(x)=1

A bag contains 10 marbles. Four of them are red, three blue, two white and one yellow. A marble is drawn at random. What is the probability it is not blue?

Answers

Probability =
(number of different successful results) / (number of all possible results) .

Number of marbles that are not blue = 7
Number of marbles in the bag = 10
Probability that one marble drawn at random is not blue = 7/10 = 70% .

For all probability questions of this type, the probability can be found as:
P_(desired)=(desired)/(total)

or, more simply:
P_(x)=(n_(x))/(n_total)

In this case:
P_(notblue)=(notblue)/(total)
P_(notblue)=(red+white+yellow)/(red+blue+white+yellow)
P_(notblue)=(4+2+1)/(4+3+2+1)
P_(notblue)=(7)/(10) = 70\%