Answer:
The equation of the line, using the point-slope form, through (-4,6) that is parallel to the line will be:
Step-by-step explanation:
We know that the slope-intercept form is
Where m is the slope and b is the y-intercept
Given the equation
comparing with the slope-intercept form
slope = m = -5
y-intercept = b = 2
We know that the parallel lines have the same slopes.
so, the slope of the parallel line will be: -5
Thus, the equation of the line, using the point-slope form, through (-4,6) that is parallel to the line will be:
Answer:
y=-x+2
Step-by-step explanation:
i already did it and your welcome in advance
²-1
We will investigate the behavior of
both the numerator and denominator of h(x) near the point where x = 1. Let
f(x)= x³ + x -2 and g(x)=x²-1. Find the local linearizations of f and g at a = 1,
and call these functions Lf(x) and Lg(x), respectively.
Lf(x) =
L₂(x) =
Explain why h(x) ≈
Lf(x)
Lg(x)
for a near a = 1.
The local linearizations of f(x) and g(x) at a = 1 are Lf(x) = 4x - 5 and Lg(x) = 2x - 2 respectively. The function h(x) ≈ Lf(x)/Lg(x) because the local linearizations provide a good approximation of the numerator and denominator of h(x) near x = 1.
The local linearization of a function at a given point is an approximation of the function using a linear equation. To find the local linearization of a function f at a = 1, we need to find the slope of the tangent line at a = 1, which is equivalent to finding the derivative of f at x = 1. By taking the derivative of f(x) = x³ + x - 2, we get f'(x) = 3x² + 1. Evaluating f'(1), we find that the slope of the tangent line at a = 1 is 4. Therefore, the local linearization of f at a = 1, denoted as Lf(x), is given by Lf(x) = f(a) + f'(a)(x - a), which becomes Lf(x) = -1 + 4(x - 1) = 4x - 5.
Similarly, to find the local linearization of g(x) = x² - 1 at a = 1, we need to find the slope of the tangent line at a = 1. The derivative of g(x) is g'(x) = 2x. Evaluating g'(1), we find that the slope of the tangent line at a = 1 is 2. Therefore, the local linearization of g at a = 1, denoted as Lg(x), is given by Lg(x) = g(a) + g'(a)(x - a), which becomes Lg(x) = 0 + 2(x - 1) = 2x - 2.
When investigating the behavior of the function h(x) = (f(x))/(g(x)) near the point x = 1, we can approximate h(x) using the local linearizations of f and g at a = 1. Near the point a = 1, h(x) ≈ Lf(x)/Lg(x) because Lf(x) and Lg(x) provide a good approximation of the numerator and denominator, respectively, of h(x). This approximation holds as long as x is close to 1.
O JXM
O JXZ
O HXJ
on edge 2020
An exteriorangle of ΔXYZ is ∠HXJ.
The correct option is D.
When two lines or rays intersect at a single point, an angle is created. The vertex is the term for the shared point. An angle measure in geometry is the length of the angle created by two rays or arms meeting at a common vertex.
As per the provided diagram, the exterior angles in the ΔXYZ are:
∠LXH,
∠MXJ,
∠HXJ,
∠OYK,
∠GZN,
∠MXZ,
∠YXL,
∠KYZ,
∠GZY.
From the given choices, ∠HXJ is an exterior angle of ΔXYZ.
To learn more about the angle measure;
#SPJ7
Answer:
The answer is C, <JXZ.
Step-by-step explanation:
Answer:
I think it's c
Step-by-step explanation:
4 times 3x equals 12x and 4 times 4x is 16x
Answer with Step-by-step explanation:
Given