It is convenient to start with the 2-point form of the equation for a line.
... y - y1 = (y2 - y1)/(x2 - x1)×(x - x1)
Either point can be (x1, y1), and the other can be (x2, y2). If we take them in order, we get
... y - 4 = (16 - 4)/(5 - 3)×(x - 3) . . . . . fill in the two points
... y = 12/2(x -3) +4 . . . . . . . . . . . . . . add 4, simpliffy a bit
... y = 6x -18 +4 . . . . . . . . . . . . . . . . . eliminate parentheses
... y = 6x -14 . . . . . . . . . . . . . . . . . . . . put in slope-intercept form
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The required reflection of the point (0, -8) on the line y = -x is (8, 0).
To determine the image of (0, -8) after a reflection over the line y = -x.
the equation is the relationship between variables and represented as y = ax + b is an example of a polynomial equation.
Here,
For the image of the point of the line y = -x
The reflection of point (0, - 8) is given as by swaping the value and change the sign, So the image of the point is (8, 0).
Thus, the required reflection of the point (0, -8) on the line y = -x is (8, 0).
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Answer:
(8,0)
Step-by-step explanation:
could be negative 8 but it said positive 8
positive works
check the picture below.
The graph of the Equation y= 3x- 5 with coordinates (0, 5) and (1.667, 0) is attached below.
We have,
y= 3x - 5
Now, to find the coordinates to plot one the graph put the distinct value of x as
For x= 0
y= -5
then, for x= 1
y= 3 - 5
y= -2
then, for x= 2
y= 6-5
y= 1
and, for x= 3
y= 9 - 5
y= 4
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slope intercept form is
y=mx+b
where m is the slope and b is the y intercept
the equation is given in slope intercept form so that the
slope = 3
y-intercept = -5
to graph this you will first place a point on (-5,0) since it's the y intercept.
then since the slope is rise/run and we have 3 (or 3/1) you will start at (-5,0), and from there go up 3 units and to the right one unit. where you end up will be your second point.
hope this helps
B. -16t^2+1000<_ 300
C. -16t^2+1000>_300
D.-16t^2+1000>300
Answer:
D. is the correct answer.
Step-by-step explanation:
It is given that Distance, d above ground with time 't' is given by the formula:
The negative sign with indicates that the distance is decreasing with square of time. i.e. value is getting subtracted from a value 1000.
For example, if t = 0, d = 1000 feet
If t = 2, d = -16 4 + 1000 = 936 feet
We can clearly see that when 't' is increasing, the distance 'd' is decreasing.
And at a certain time, the object will be on ground when d = 0 feet.
Inequality for the distance greater than 300 feet i.e.
d > 300 feet
Hence, the inequality will be:
is the correct answer.