Solve by graphing. x2 + 2x – 3 = 0

Answers

Answer 1
Answer:

The graph of an equation is the set of all  points that are solutions of the equation. Frequently, a relationship between two quantities can be expressed as an equation  in two variables. For instance, we can write the equation of our problem as the following form:


y=x^2+2x-3 \n \n Or: \n \n f(x)=x^2+2x-3


So, by graphing f(x) we want to know the x-intercepts. This graph is illustrated in the Figure below. As you can see, points in red are the solution to this problem that are the x-intercepts of our previously defined function f(x). These points are:


(-3,0) \ and \ (1,0)

Answer 2
Answer:

The solutions of the given quadratic equation are x=-3 and x=1.

The given quadratic equation is x²+2x-3=0.

By using splitting middle term method, the given equation can be solved as follows:

Here, x²+3x-x-3=0

x(x+3)-1(x+3)=0

(x+3)(x-1)=0

x+3=0 and x-1=0

x=-3 and x=1

Therefore, the solutions of the given quadratic equation are x=-3 and x=1.

To learn more about the solution of quadratic equation visit:

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Related Questions

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The diagonals of parallelogram ABCD intersect at point E. Which of the following statements is not necessarily true?a. BD bisect AC
b. AB=CD
c. BAD=BCD
d. AC=BD

Answers

Answer:

(D)

Step-by-step explanation:

It is given that The diagonals of parallelogram ABCD intersect at point E.

then, using the properties of parallelogram, we get

(A) BD bisects AC

This is correct statement because the diagonals bisect each other in parallelogram.

(B) AB=CD

This is correct statement because the opposite sides of the parallelogram are equal.

(C) ∠BAD=∠BCD

This is correct because opposite angles of the parallelogram are equal.

(D) AC=BD

This is not necessarily true, because if the diagonals of parallelogram are equal, then it is a rectangle.

Hence, option D is correct option that is not necessarily true.

I hope this helps you

Work out the area of a semicircle with radius 3cm. Give your answer in terms of pie

Answers

Answer:

Step-by-step explanation:

To find the area of a semicircle, you can follow these steps:

1. Recall that the formula for the area of a circle is A = πr^2, where A represents the area and r represents the radius.

2. Since a semicircle is half of a circle, the formula for the area of a semicircle is A = (πr^2)/2.

3. In this case, the radius of the semicircle is given as 3cm. Plug this value into the formula: A = (π * 3^2)/2.

4. Simplify the equation: A = (π * 9)/2.

5. The final answer, in terms of π, is A = 4.5π square centimeters.

Therefore, the area of the semicircle with a radius of 3cm is 4.5π square centimeters

What is the value of the slope of the graph of distance versus time, and what does the slope represent?

Answers

To find the slope of the graph you pick any piece of the line, and divide the vertical difference between its ends by the horizontal difference between its ends. If the graph is distance versus time then the slope represents the speed.

Suppose that y varies inversely with x. Write an equation for the inverse variation. Y =4 when x =7

Answers

If y varies inversely as x, then we write it as:
y = k/x

where k is some constant.

If we multiply both sides of this equation by x we get an equation for k:
k = x*y

We are given that y=4 when x=7, therefore:
k = 7*4 = 28

Put this back into our original equation to get:
y = 28/x

the ratio of the circumferences of two circles is 2:3. If the large circle has a radius of 39 cm, what is the radiusof the small circle?

Answers

Answer:

r_(1) = 26.

Step-by-step explanation:

Given : the ratio of the circumferences of two circles is 2:3. If the large circle has a radius of 39 cm,

To find : what is the radius of the small circle.

Solution : We have given that ratio of the circumferences of two circles is 2:3.

Let r_(2)  is radius of larger circle and  r_(1)  is radius of small circle .

Then circumference = (2\pi\ r_(1) )/(2\pi\ r_(2)) = (2)/(3) .

Solving the above equation

(r_(1))/(r_(2) ) =  (2)/(3) .

We have given radius of larger circle = 39 then

(r_(1))/(39) =  (2)/(3) .

On multiplying both sides by 39.

r_(1) = 39 *(2)/(3).

r_(1) = 13 * 2.

r_(1) = 26.

Therefore, r_(1) = 26.

C1/C2 =  2/3

 2pi r1 / 2pi r2 = r1/r2 = 2/3

r1/39 = 2/3

r1 = 39*2/3 = 26

So, your answer is 26cm

A rectangular plot of ground is 5 meters longer than it is wide. Its area is 20,000 square meters.which equation will help you find dimensions?
Let w=width
a- w+2(w+5)=20,000
b- w(w+5)=20,000
c- (w(w+5))/2 = 20,000
d- w^2=20,000+5

Answers

Answer:

b- w(w+5)=20,000

Step-by-step explanation:

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