We know that a parallel line has the same slope. And the slope-intercept form in y=mx+b.
1. simplify x-y=7 to isolate y.
subtract x: -y=-x+7
then divide by -1: y=x-7
so the slope is 1 (m=1)
2. plug in m=1 and (1,0) *******alternate solution below
0=1(1)+b
0=1+b subtract 1
-1=b (b=-1)
3. y=mx+b plug in numbers. ( in bold)
y=1x-1
your answer is y=x-1
*****alternate answer solution from step 2 (using step 1)
2. use the formula y-y1=m(x-x1) (y1 and x1 is with the 1 below the letters BTW)
plug in (1,0)
y-0=1(x-1)
y=1x-1
y=x-1 is your answer.
So it comes out as the same answer. Just 2 different ways to doing it! :)
Answer:
See Explanation
Step-by-step explanation:
The question is incomplete as Micah's workings is not attached. So, there's no way to determine where Micah's error is.
However, I'll solve for the vertex of the given function.
Given
Vertex, V is of the form:
Where
and
Solving for h:
So:
Solving for k
Substitute 2.5 for x in
Hence:
The vertex is
The correct vertex for the function is (2.5, 122.375).
The given function is .
To find the vertex of a quadratic function in the form , we can use the formula x = -b / (2a) to find the x-coordinate of the vertex.
In this case, the coefficient of is -9.5, the coefficient of x is 47.5, and there is no constant term.
Using the formula, we can find the x-coordinate of the vertex:
Now, substitute this x-coordinate back into the original function to find the y-coordinate:
Therefore, the correct vertex for the function is (2.5, 122.375).
Micah's error might be related to incorrectly calculating the x-coordinate of the vertex or substituting the wrong value back into the function.
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Answer:
r≈1.78
Step-by-step explanation:
(1, 3)
(0, 3)
(0, 4)
The point that is not the solution to the system of inequalities is (2, 3), the correct option is A.
A system of Inequality is a set of inequalities in one or more variables.
The inequalities in the graph have a common solution shown by the shaded area.
The points (1,3), (0,3) and (0,4) lie in the shaded region.
Point (2,3) is out of the shaded area.
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For a point to be a solution, it has to be on the green shaded area including the solid red line to the left above the intersection of the lines but not the dashed red line to the right.
(2, 3) is outside the shaded area, so it is not a solution.
(1, 3) is inside the green shaded area, so it is a solution.
(0, 3) is on the red line above the intersection, so it is a solution.
(0, 4) is inside the green shaded area, so it is a solution.
Answer: A. (2, 3)
Answer:
Step-by-step explanation:
The given data set is:
23, 29, 12, 14, 27, 23, 23, 18, 23, 1, 7, 18, 43, 24, 28, 17, 32, 33, 38
firstly arrange the given data set in ascending order, we have
1, 7, 12, 14, 17, 18, 18, 23, 23, 23, 23, 24, 27, 28, 29, 32, 33, 38, 43
Now, Mode is the observation point which occurs frequently in the given data set, thus
Mode=23
Mean is given as:
≈
Median of the given data set is the middle value of the given set, thus
Median=23
Hence, the value that would best describe the central tendency is 23. Since, the values to the left of 23 are more scattered than those to its right, the distribution exhibits negative.