कम्प्युटरको गति मापन गर्ने एकाइहरूलाई वर्णन गर्नुहोस् ।​

Answers

Answer 1
Answer:

Answer:

मापनको एकाईलाई हर्ट्ज (हर्ट्ज) भनिन्छ, जुन प्रति सेकंड टेक्निकली एक चक्र हो, घडीको गति मापन गर्न प्रयोग हुन्छ। ... कम्प्युटरको घडी गति सामान्यतया मेगाहेर्ट्झ (मेगाहर्ट्ज) वा गिगाहर्ट्ज (GHz) मा मापन गरिएको छ। एक मेगाहेर्ट्ज प्रति सेकेन्ड १० लाख टिक्स बराबर हुन्छ, र एक गिगाहर्ट्ज बराबर एक सेकेन्ड टिक टिक प्रति सेकेन्ड।


Related Questions

One question in the survey asked how much time per year the children spent in volunteer activities. The sample mean was 14.76 hours and the sample standard deviation was 16.54 hours.Required:a. Based on the reported sample mean and sample standard deviation, explain why it is not reasonable to think that the distribution of volunteer times for the population of South Korean middle school students is approximately normal. b. The sample size was not given in the paper, but the sample size was described as large. Suppose that the sample size was 500. Explain why it is reasonable to use a one-sample t confidence interval to estimate the population mean even though the population distribution is not approximately normal. c. Calculate and interpret a confidence interval for the mean number of hours spent in volunteer activities per year for South Korean middle school children.
You have been waiting for months. The latest version of your favorite video game comes out today. You have mowed lawns, done extra chores, and saved up gift money. The new game costs $49.99. You have exactly $50.00 saved. So you are good to go, right? In 3 to 5 sentences explain if you have enough money to buy that game in Pennsylvania where sales tax is 6%. If you have enough money, will you have change? If you do not have enough money, how much more do you need?
Can someone please help me with this question so i can i get my grades up: (2/9v)−(−1/3v+5/9)
What is the y value of the line when x = -1
EquationsSolve T = C(9+ AB) for B

Which expression shows the prime factorization of 40? 2 × 2 × 5 2 × 2 × 2 × 5 2 × 5 × 5 2 × 5 × 5 × 5

Answers

Answer:

2 × 2 × 2 × 5

Step-by-step explanation:

2 × 2 =4×2 =8×5=40

Answer:

2·2·2·5

Step-by-step explanation:

2·2=4·2=8·4=40

Patricia, audrey, and laticia are in a nursery buying plants for their gardens. Patricia orders six magnolias and two camellias. Audrey orders four camellias and three azaleas. leticia orders three magnolias, two camellias, and four azaleas. If patricia, audrey, and leticia paid $168.00, $150.30, and $222.50 respectively, what are the individual costs of a magnolia, a camellia, and an azalea?

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Answer:

The cost of each magnolia plant is $23.24, the cost of each camellia plant is $14.28, and the cost of each azalea plant is $31.05.

Step-by-step explanation:

I attached the explanation.

Help asapppp pleaseeeeeee

Answers

3 and 4 , 3.872
5 and 6 , 5.292
7 and 8 , 7.874
8 and 9 , 8.718
10 and 11 , 10.247

16
16
41
64
1322 3230
16
20
What is the mean
here?

Answers

Answer:

590.625

Step-by-step explanation:

Add up all data values to get the sum

Count the number of values in your data set

Divide the sum by the count

Answer:

590.625

Step-by-step explanation:

To find the mean, add up all of the values then divide by the amount of values there are.

The total amount is 16 +16+ 41+ 64+ 1322+ 3230+ 16+ 20 = 4725

There are 8 total values so you divide by 8

590.625

3x-165=7x=105
What is x?

Answers

Answer:

tutoring is available right now

A baseball is hit inside a baseball diamond with a length and width of 90 feet each. What is the probability that the ball will bounce on the pitchers mound, if the diameter of the mound is 18 feet? Assume that the ball is equally likely to bounce anywhere in the infield. When applicable, leave your answer in terms of pie and include all necessary calculations.

Answers

Answer:

(\pi )/(100)

Step-by-step explanation:

The first thing to notice is that the diamond is just a square rotated 45 degrees square, with 90 feet sides, so the total area of the diamond is:

A(square)= l x l = 90 ft * 90 ft = 8100 ft^(2)

We also need to calculate the area of the mound, assuming it being a circle:

A(circle)= \pi * r^(2)  And r=diameter/2= 18 ft/2 = 9 ft

A(circle) =  \pi * (9 ft)^(2) = 81\pi ft^(2)

Now since the ball has an equal chance of bouncing anywhere in the field, the probability would be the ratio of the area occupied by the mound inside of the diamond.

P= (81\pi ft^(2))/(8100 ft^(2))=(\pi )/(100)

90(squared) + 90 (squared) = C (squared)
(we use 90 because the base path is 90 ft long since the diamond is a square that makes all sides 90 ft long)
8100 + 8100 = c(squared)
16200 = c(squared)
we will get the square root of 16200 to get the diagonal length
C=127.3 ft, and since it is the diagonal distance we will device it to 2, to get the distance from the pitcher ro the 2nd base.
127.3/2 = 67.7 ft.
67.7 ft is the distance from the pitcher to the 2nd base.