Why does the chemical reaction seen here obey the law of conservation of matter?
Answer:
Explanation
NaOH + HCl -----> NaCl + H2O
Answer:
B. Two chlorine atoms
Explanation:
This electronic configuration shows that the given atom is magnesium.
Electronic configuration of magnesium:
Mg¹² = 1s² 2s² 2p⁶ 3s²
There are two valance electrons of magnesium that's why it would react with two atoms of chlorine. Chlorine is present in seventeen group. It has seven valance electrons. It required just one electron to get complete octet. While magnesium needed to lose two electrons to get complete octet. That's why two chlorine atoms bonded with one magnesium atom. Thus both would get complete octet.
Mg + Cl₂ → MgCl₂
The size of the container needed to hold the gas is 1.03 L
The volume of the container needed can obtained by using the ideal gas equation as illustrated below:
PV = nRT
Divide both side by P
V = nRT / p
V = (0.0459 × 0.0821 × 273) / 1
V = 1.03 L
Therefore, the size of the container needed is 1.03 L.
Learn more about ideal gas equation:
Answer:
The size of the container needed is 1,03 liters
Explanation:
We use the formula PV=nRT. The STP conditions correspond to 1 atm of pressure and 273 K of temperature.
PV=nRT V=(nRT)/P
V= (0,0459 mol x 0,082 l atm/ K mol x 273K)/1 atm= 1,0275174 liters
Answer:
C3H6 + Br2 = C3H6Br2
The product formed is 1,2-dibromopropane.
The red-brown color of the bromine disappears, leaving a colorless liquid
Explanation:
C3H6 + Br2 = C3H6Br2
The product formed is 1,2-dibromopropane.
This is a direct addition reaction. The one molecule of bromine (Br2) joins the organic compound C3H6 to form one molecule of C3H6Br2.
This seemed unlikely at first, but one must look more closely at the C3H6. This is not a straight alkane (e.g., propane). Propane has the formula C3H8:
H3-C-C2-CH3
The molecule C3H6 is propylene (or propene). It has a double bond between two carbons.
H3-CH-CH=CH2
The compound in the question is propylene. When exposed to bromine, the carbon double bond breaks and a bromine atom is attached to each carbon:
H3-CH-CH=CH2 + Br2 = H3-CH-CHBr-CHBr
When propene reacts with bromine, the red-brown color of the bromine is lost and the product is a colorless liquid.
Given:
Molar mass of CO2 = 44.01g/mol
3.21x10^25 molecules of CO2
Required:
Mass of CO2
Solution:
Avogadro’s number states that for every mole of atom, there are 6.023x10^23 units of atom. The units may be formula units, atoms. In here, you need to divide 3.21x10^25 molecules of CO2 to 6.023x10^23 molecules per mole.
3.21x10^25 molecules of CO2 / 6.023x10^23 molecules per mole = 53.30 moles CO2
53.30 moles CO2 (44.01g/mol CO2) = 2346 g of CO2