You can differentiate between sodium and calcium ions using sodium carbonate by observing a precipitation reaction. Sodium carbonate reacts with calcium ions to form a solid precipitate of calcium carbonate, while sodium ions remain in solution.
To differentiate between the sodium ion (Na+) and the calcium ion (Ca2+) in a solution of Na2CO3, a type of precipitation reaction can be used. Sodium carbonate (Na2CO3) can react with calcium ions (Ca2+) to form calcium carbonate (CaCO3) and 2 sodium ions (Na+), which is a precipitate reaction. This is because calcium carbonate is insoluble in water and will form a solid precipitate, while sodium ions will remain in solution.
The balanced reaction equation is: Na2CO3(aq) + Ca2+(aq) → CaCO3(s) + 2Na+(aq).
As the sodium continues to exist in the solution and does not form a precipitate, it can be differentiated from the calcium.
#SPJ11
an implosion
an endothermic process
a phase change
(please explain! Do not jus give me the answer... I know its not B or
d.
Answer is: (3) 2–8–17–6.
1) This is ground state of sodum atom.
Electron configuration of sodium atom: ₁₁Na 1s² 2s² 2p⁶ 3s¹.
Atomic number of sodium is 11, it means that it has 11 protons and 11 electrons, so atom of sodium is neutral.
2) This is ground state of sulfur atom.
Sulfur electron configuration: ₁₆S 1s²2s²2p⁶3s²3p⁴.
Sulfur has six valence electrons (3s²3p⁴), in 3s orbital, two electrons are paired, in 3p orbital, two electrons are paired and two are unpaired.
4) This is ground state of arsenic atom.
Electron configuration of arsenic atom:
₃₃As 1s² 2s² 2p⁶ 3s² 3p⁶ 3d¹⁰ 4s² 4p³.
Electron configuration represents an excited state : (3) 2–8–17–6
In an atom there are levels of energy in the shell and sub shell
This energy level is expressed in the form of electron configurations.
Writing electron configurations starts from the lowest to the highest sub-shell energy level. There are 4 sub-shells in the shell of an atom, namely s, p, d and f. The maximum number of electrons for each sub shell is
Charging electrons in the sub shell uses the following sequence:
1s², 2s², 2p⁶, 3s², 3p⁶, 4s², 3d¹⁰, 4p⁶, 5s², 4d¹⁰, 5p⁶, 6s², etc.
Determination of electron configurations based on principles:
According to Niels Bohr, electrons surround the nucleus of an atom on a path called the electron shell. Each shell has an energy level. The further from the core, the higher the energy level
Maximum electrons of shells :
The maximum number of electrons in each shell can be formulated = 2n² (n = shell number)
Electrons can move the shell up or down by releasing energy or absorbing energy
Excited electrons show higher electron transfer to the shell by absorbing energy
So it can be concluded that there are 2 conditions :
Ground state is the state of electrons filling skins with the lowest energy levels.
Excited state is the state of electrons which occupy a higher energy level
The state of excited electrons can be seen from the presence of electrons which do not fill the skin completely but fill the skin afterwards
From the electron configuration , option 3 shows the excitation of one electron in the M shell towards the N shell, which should have a configuration in the ground state:
2–8–18–5
element X
electrons and atomic orbitals
about subatomic particles statement
Keywords: electron configurations, the shell of atoms, excited state
number of moles
volume and moles of gas
pressure and temperature
Given from the combined gas law that PV/T = k, there, therefore, the number of moles of the gas is constant.
According to the combined gas law, the product of the pressure and volume divided by the temperature is a constant. That is; PV/T = k
Looking at this statement we can see that the implied assumption in this law is that the number of moles of the gas is constant.
Learn more about gas law:brainly.com/question/13805601?
Answer:
number of moles
Explanation:
I believe this is the right one :)
False