B. similar to other minerals
C. variable depending on where its found
D. influenced by heat and light
b. 16 g
c. 32 g
d. 1.204 × 1024
The correct answer is B.
1 mol O2 x 15.999 O2/ 1 mol O2 = 15.999 O2
16 O2 when rounded.
The empirical formula is No2 and molecular formula is N2O4
find the moles of each reactant
=% composition/molar mass
molar mass of oxygen=16 g/mol ,while hat of nitrogen= 14 g/mol from periodic table
moles is therefore=
nitrogen= 30.43/14=2.174 moles
oxygen= 69.57/1 6=4.348 moles
find the mole ratio by dividing each moles with smallest number of mole( 2.174)
nitrogen = 2.174/2.174= 1
oxygen = 4.348/2.174=2
therefore the empirical formula= NO2
molecular formula calculation
[NO2] n= 92.02 amu
[(14) + (16x2)]n = 92.02 amu
46n= 92.02
divide both side by 46
n=2
therefore the molecular formula is gotten by multiplying the empirical formula by 2= [NO2]2= N2O4
This hypothetical process would produce actinium-230.
An alpha decay reduces the atomic number of a nucleus by two and its mass number by four.
There are two types of beta decay: beta minus β⁻ and beta plus β⁺.
The mass number of a nucleus stays the same in either process. In β⁻ decay, the atomic number increases by one. An electron e⁻ is produced. In β⁺ decay, the atomic number decreases by one. A positron e⁺ is produced. Positrons are antiparticles of electrons.
β⁻ are more common than β⁺ in decays involving uranium. Assuming that the "beta decay" here refers to β⁻ decay.
Gamma decays do not influence the atomic or mass number of a nucleus.
Uranium has an atomic number of 92. 238 is the mass number of this particular isotope. The hypothetical product would have an atomic number of 92 - 2 ⨯ 2 + 1 = 89. Actinium has atomic number 89. As a result, the product is an isotope of actinium. The mass number of this hypothetical isotope would be 238 - 2 ⨯ 4 = 230. Therefore, actinium-230 is produced.
The overall nuclear reaction would involve five different particles. On the reactant side, there is
On the product side, there are
Consider: what would be the products if the nucleus undergoes a β⁺ decay instead?