PLease help me with this i am having soo much truble with itA family is having a pool built in their backyard. If their yard is rectangular and measures 7x by 6x and the pool is circular with a radius of 2x how much of the yard will be left over after the pool is built?
a. 38x2
b. 42x2 – 4x2
c. 42x2 – 2x2
d. 38x2
Answers
A 1 = L x W = 7 x * 6 x = 42 x²
Area of a pool :
A 2 = r² π = ( 2 x )² π = 4 x² π
A = A 1 - A 2 = 42 x² - 4 x² π
The answer must be in terms of π:
B ) 42 x² - 4 x² π
Related Questions
What is the formula to find the depth of a cube
Let f (x) 4x -5 and g (x)= 6x -3 find f (x) - g (x)
how tall are sally and anna if sally is 0.1m taller than anna and their combined height is 3.16 meters
The table below shows data from a survey about the amount of time, in hours, high school students spent reading and the amount of time spent watching videos each week (without reading): Reading Video 3 1 3 2 4 3 5 4 6 6 7 7 10 8 12 8 14 9 30 15 Which response best describes outliers in these data sets? A, Reading has a suspected outlier in the 30-hour value. B. Reading has a suspected outlier in the 30-hour value, and video has a possible outlier in the 15-hour value. C. Neither data set has suspected outliers. D. The range of data is too small to identify outliers.
Answers
DEFINITION
rhombus is a parallelogram with four sided equal a parallelogram whose all sides are equal is called a rhombus
PROPERTIES
- all side are equal length
- each pair of opposite sides are equal
- opposite angles are equal
- diagonals of a rhombus are perpendicular bisector each other
Answers
Answer:
To work this out you need to multiply 3/4 by 1/6.
=3/24
=1/8
Step-by-step explanation:
Hope this helps :)
Final answer:
The scientist used 1/8 of the bottle.
Explanation:
To find out how much of the bottle the scientist used, we need to multiply the fraction of the solution used (1/6) by the fraction of the bottle filled with the solution (3/4).
The solution used = (1/6) * (3/4) = 3/24 = 1/8.
Therefore, the scientist used 1/8 of the bottle.
Learn more about Fraction here:
#SPJ2
Answers
Answer:
To solve the system of linear equations using Gaussian elimination, we'll write the augmented matrix and perform row operations to transform it into row echelon form.
The given system of equations:
-2x_1 + 3x_2 + x_3 = 2
-3x_1 + 4x_2 + 2x_3 = 2
x_1 - 5x_2 + 4x_3 = -9
-2x_1 + 4x_2 - 4x_3 = 8
Writing the augmented matrix:
[ -2 3 1 | 2 ]
[ -3 4 2 | 2 ]
[ 1 -5 4 | -9 ]
[ -2 4 -4 | 8 ]
1. Row 1 Ã (-3) + Row 2 â Row 2:
[ -2 3 1 | 2 ]
[ 9 -13 -5 | -6 ]
[ 1 -5 4 | -9 ]
[ -2 4 -4 | 8 ]
2. Row 1 Ã (1/2) + Row 3 â Row 3:
[ -2 3 1 | 2 ]
[ 9 -13 -5 | -6 ]
[ -1 (3/2) 2 | -5/2]
[ -2 4 -4 | 8 ]
3. Row 1 Ã (-1) + Row 4 â Row 4:
[ -2 3 1 | 2 ]
[ 9 -13 -5 | -6 ]
[ -1 (3/2) 2 | -5/2]
[ 0 7 -3 | 6 ]
4. Row 2 Ã (-9/7) + Row 3 â Row 3:
[ -2 3 1 | 2 ]
[ 9 -13 -5 | -6 ]
[ -1 0 (59/7) | -(23/7)]
[ 0 7 -3 | 6 ]
5. Row 2 Ã (2/3) + Row 4 â Row 4:
[ -2 3 1 | 2 ]
[ 9 -13 -5 | -6 ]
[ -1 0 (59/7) | -(23/7)]
[ 0 0 (-11/7) | 0 ]
6. Row 3 Ã (-14/11) + Row 4 â Row 4:
[ -2 3 1 | 2 ]
[ 9 -13 -5 | -6 ]
[ -1 0 (59/7) | -(23/7)]
[ 0 0 1 | 0 ]
7. Row 3 Ã (1/2) + Row 1 â Row 1:
[ -1 3/2 3/2 | (4/7) ]
[ 9 -13 -5 | -6 ]
[ -1 0 1 | 0 ]
[ 0 0 1 | 0 ]
8. Row 3 Ã (9/7) + Row 2 â Row 2:
[ -1 3/2 3/2 | (4/7) ]
[ 0 -26/7 -14/7 | -42/7 ]
[ -1 0 1 | 0 ]
[ 0 0 1 | 0 ]
9. Row 3 Ã (1/2) + Row 4 â Row 4:
[ -1 3/2 3/2 | (4/7) ]
[ 0 -26/7 -14/7 | -42/7 ]
[ -1 0 1 | 0 ]
[ 0 0 1 |
Answers
1 + sin² t / cos² t = 1 / cos² t
( This is because we know that tan x = sin x / cos x and csc x = 1 / cos x )
Then we will multiply both sides of an equation by cos² t
1 * cos² t + sin² t * cos² t / cos² t = 1
cos² t + sin² t = 1 ( and we know that it is the identity - true )
2 ) 1 + cot ² t = csc² t
1 + cos² t / sin² t = 1 / sin² t / · sin² t ( multiply both sides by sin² t )
sin² t + cos² t = 1 ( true )
Answers
Answer: 7x + 4y + 8.
Step-by-step explanation:
Given data:
15 + 12x -5x +4y -7
Solution:
15 + 12x -5x +4y -7
Subtract the numbers
= 8 + 12x – 5x + 4y
Collect like terms
= 8 + 7x + 4y
Rearrange the equation
= 7x + 4y + 8
1. 2(x2 + 5) = 60 1.
2. 2x2 + 10 = 60 2.
3. 2x2 = 50 3.
4. x2 = 25 4.
5. x = ±5 5.
Answers
2(x²+5)=60
<==>x²+5=30 (divided teh 2 members by the positive 5 :keep the equality)
<==>x²-25=0 (substract 25 from 2 members)
<==>(x-5)(x+5)=0 (remarquable product a²-b²=(a+b)(a-b))
<==> x= 5 or x=-5 (a product if null if one at least of its factor is null)